Chapter 38 AP Objectives

Chapter 38     Plant reproduction and Development
Objectives
Sexual Reproduction
1. In general terms, explain how the basic plant life cycle with alternation of generations is modified in angiosperms.
2. List four floral parts in order from outside to inside a flower.
3. From a diagram of an idealized flower, correctly label the following structures and describe the function of each structure:
a. sepals
b. petals
c. stamen (filament and anther)
d. carpel (style, ovary, ovule, and stigma)
4. Distinguish between:
a. complete and incomplete flowers
b. bisexual and unisexual flowers
c. monoecious and dioecious plant species
5. Explain by which generation, structure, and process spores are produced.
6. Explain by which generation, structure, and process gametes are produced.
7. Name the structures that represent the male and female gametophytes of flowering plants.
8. Describe the development of an embryo sac and explain the fate of each of its cells.
9. Explain how pollen can be transferred between flowers.
10. Distinguish between pollination and fertilization.
11. Describe mechanisms that prevent self-pollination.
12. Outline the process of double fertilization. Explain the adaptive advantage of double fertilization in angiosperms.
13. Explain how fertilization in animals is similar to that in plants.
14. Describe the fate of the ovule and ovary after double fertilization. Note where major nutrients are stored as the embryo develops.
15. Describe the development and function of the endosperm. Distinguish between liquid endosperm and solid endosperm.
16. Describe the development of a plant embryo from the first mitotic division to the embryonic plant with rudimentary organs.
17. From a diagram, identify the following structures of a seed and state a function for each:
a. seed coat
b. proembryo
c. suspensor
d. hypocotyls
e. radicle
f. epicotyl
g. plumule
h. endosperm
i. cotyledons
j. shoot apex
18. Explain how a monocot and dicot seed differ.
19. Explain how fruit forms and ripens.
20. Distinguish among simple, aggregate, and multiple fruit. Give an example of each type of fruit.
21. Explain how selective breeding by humans has changed fruits.
22. Explain how seed dormancy can be advantageous to a plant. Describe some conditions for breaking dormancy.
23. Describe the process of germination in a garden bean.
Asexual Reproduction
24. Describe the natural mechanisms of vegetative reproduction in plants, including fragmentation and apomixis.
25. Explain the advantages and disadvantages of reproducing sexually and asexually.
26. Explain various methods that horticulturalists use to propagate plants from cuttings.
27. Explain how the technique of plant tissue culture can be used to clone and genetically engineer plants.
28. Describe the process of protoplast fusion and its potential agricultural impact.
Plant Biotechnology
29. Compare traditional plant-breeding techniques and genetic engineering, noting similarities and differences.
30. Describe two transgenic crops.
31. Describe some of the biological arguments for and against genetically modified crops.
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chapter 39 ap objectives

 

 Chapter 39     Control Systems in Plants
Objectives
Signal Transduction and Plant Responses
1. Compare the growth of a plant in darkness (etiolation) to the characteristics of greening (de-etiolation).
2. Describe the signal pathways associated with de-etiolation.
3. Describe the role of second messengers in the process of de-etiolation.
4. Describe the two main mechanisms by which a signaling pathway can activate an enzyme.
5. Explain, using several examples, what researchers have learned about the activity of plant hormones by study of mutant plants.
Plant Responses to Hormones
6. For the following scientists, describe their hypothesis, experiments, and conclusions about the mechanism of phototropism:
a. Charles and Francis Darwin
b. Peter Boysen-Jensen
c. Frits Went
7. List six classes of plant hormones, describe their major functions, and note where they are produced in the plant.
8. Explain how a hormone may cause its effect on plant growth and development.
9. Describe a possible mechanism for the polar transport of auxin.
10. According to the acid growth hypothesis, explain how auxin can initiate cell elongation.
11. Explain why 2,4-D is widely used as a weed killer.
12. Explain how the ratio of cytokinin to auxin affects cell division and cell differentiation.
13. Describe the evidence that suggests that factors other than auxin from the terminal bud may control apical dominance.
14. Describe how stem elongation and fruit growth depend on a synergism between auxin and gibberellins.
15. Explain the probable mechanism by which gibberellins trigger seed germination.
16. Describe the functions of brassinosteroids in plants.
17. Describe how abscisic acid (ABA) helps prepare a plant for winter.
18. Describe the effects of ABA on seed dormancy and drought stress.
19. Describe the role of ethylene in the triple response to mechanical stress, apoptosis, leaf abscission, and fruit ripening.
Plant Responses to Light
20. Define photomorphogenesis and note which colors are most important to this process.
21. Compare the roles of blue-light photoreceptors and phytochromes.
22. Describe the phenomenon of chromophore photoreversibility and explain its role in light-induced germination of lettuce seeds.
23. Define circadian rhythm and explain what happens when an organism is artificially maintained in a constant environment.
24. List some common factors that entrain biological clocks.
25. Define photoperiodism.
26. Distinguish among short-day, long-day, and day-neutral plants. Explain why these names are misleading.
27. Explain what factors other than night length may control flowering and what is necessary for flowering to occur.
Plant Responses to Environmental Stimuli Other than Light
28. Describe how plants apparently tell up from down. Explain why roots display positive gravitropism and shoots exhibit negative gravitropism.
29. Distinguish between thigmotropism and thigmomorphogenesis.
30. Describe how motor organs can cause rapid leaf movements.
31. Provide a plausible explanation for how a stimulus that causes rapid leaf movement can be transmitted through the plant.
32. Describe the challenges posed by, and the responses of plants to, the following environmental stresses: drought, flooding, salt stress, heat stress, and cold stress.
Plant Defense: Responses to Herbivores and Pathogens
33. Explain how plants deter herbivores with physical and chemical defenses.
34. Describe the multiple ways that plants defend against pathogens.
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Chapter 3 – Water and the Fitness of the Environment – Lecture Outline

Chapter 3    Water and the Fitness of the Environment    Lecture Outline

Overview: The Molecule That Supports All of Life

  • Because water is the substance that makes life possible on Earth, astronomers hope to find evidence of water on newly discovered planets orbiting distant stars.
  • Life on Earth began in water and evolved there for 3 billion years before colonizing the land.
  • Even terrestrial organisms are tied to water.
  • Most cells are surrounded by water.
  • Cells are about 70–95% water.
  • Water is a reactant in many of the chemical reactions of life.
  • Water is the only common substance that exists in the natural world in all three physical states of matter: solid ice, liquid water, and water vapor.

Concept 3.1 The polarity of water molecules results in hydrogen bonding

  • In a water molecule, two hydrogen atoms form single polar covalent bonds with an oxygen atom.
  • Because oxygen is more electronegative than hydrogen, the region around the oxygen atom has a partial negative charge.
  • The regions near the two hydrogen atoms have a partial positive charge.
  • A water molecule is a polar molecule in which opposite ends of the molecule have opposite charges.
  • Water has a variety of unusual properties because of the attraction between polar water molecules.
  • The slightly negative regions of one water molecule are attracted to the slightly positive regions of nearby water molecules, forming hydrogen bonds.
  • Each water molecule can form hydrogen bonds with up to four neighbors.

Concept 3.2 Four emergent properties of water contribute to Earth’s fitness for life

  • Organisms depend on the cohesion of water molecules.
  • The hydrogen bonds joining water molecules are weak, about 1/20 as strong as covalent bonds.
  • They form, break, and reform with great frequency. Each hydrogen bond lasts only a few trillionths of a second.
  • At any instant, a substantial percentage of all water molecules are bonded to their neighbors, creating a high level of structure.
  • Collectively, hydrogen bonds hold water together, a phenomenon called cohesion.
  • Cohesion among water molecules plays a key role in the transport of water and dissolved nutrients against gravity in plants.
  • Water molecules move from the roots to the leaves of a plant through water-conducting vessels.
  • As water molecules evaporate from a leaf, other water molecules from vessels in the leaf replace them.
  • Hydrogen bonds cause water molecules leaving the vessels to tug on molecules farther down.
  • This upward pull is transmitted down to the roots.
  • Adhesion, clinging of one substance to another, contributes too, as water adheres to the wall of the vessels.
  • Surface tension, a measure of the force necessary to stretch or break the surface of a liquid, is related to cohesion.
  • Water has a greater surface tension than most other liquids because hydrogen bonds among surface water molecules resist stretching or breaking the surface.
  • Water behaves as if covered by an invisible film.
  • Some animals can stand, walk, or run on water without breaking the surface.
  • Water moderates temperatures on Earth.
  • Water stabilizes air temperatures by absorbing heat from warmer air and releasing heat to cooler air.
  • Water can absorb or release relatively large amounts of heat with only a slight change in its own temperature.
  • Atoms and molecules have kinetic energy, the energy of motion, because they are always moving.
  • The faster a molecule moves, the more kinetic energy it has.
  • Heat is a measure of the total quantity of kinetic energy due to molecular motion in a body of matter.
  • Temperature measures the intensity of heat in a body of matter due to the average kinetic energy of molecules.
  • As the average speed of molecules increases, a thermometer will record an increase in temperature.
  • Heat and temperature are related, but not identical.
  • When two objects of different temperatures come together, heat passes from the warmer object to the cooler object until the two are the same temperature.
  • Molecules in the cooler object speed up at the expense of kinetic energy of the warmer object.
  • Ice cubes cool a glass of pop by absorbing heat from the pop as the ice melts.
  • In most biological settings, temperature is measured on the Celsius scale (°C).
  • At sea level, water freezes at 0°C and boils at 100°C.
  • Human body temperature is typically 37°C.
  • While there are several ways to measure heat energy, one convenient unit is the calorie (cal).
  • One calorie is the amount of heat energy necessary to raise the temperature of one g of water by 1°C.
  • A calorie is released when 1 g of water cools by 1°C.
  • In many biological processes, the kilocalorie (kcal) is more convenient.
  •  A kilocalorie is the amount of heat energy necessary to raise the temperature of 1000 g of water by 1°C.
  • Another common energy unit, the joule (J), is equivalent to 0.239 cal.
  • Water stabilizes temperature because it has a high specific heat.
  • The specific heat of a substance is the amount of heat that must be absorbed or lost for 1 g of that substance to change its temperature by 1°C.
  • By definition, the specific heat of water is 1 cal per gram per degree Celsius or 1 cal/g/°C.
  • Water has a high specific heat compared to other substances.
  • For example, ethyl alcohol has a specific heat of 0.6 cal/g/°C.
  • The specific heat of iron is 1/10 that of water.
  • Water resists changes in temperature because of its high specific heat.
  • In other words, water absorbs or releases a relatively large quantity of heat for each degree of temperature change.
  • Water’s high specific heat is due to hydrogen bonding.
  • Heat must be absorbed to break hydrogen bonds, and heat is released when hydrogen bonds form.
  • Investment of one calorie of heat causes relatively little change to the temperature of water because much of the energy is used to disrupt hydrogen bonds, not speed up the movement of water molecules.
  • Water’s high specific heat has effects that range from the level of the whole Earth to the level of individual organisms.
  • A large body of water can absorb a large amount of heat from the sun in daytime during the summer and yet warm only a few degrees.
  • At night and during the winter, the warm water will warm cooler air.
  • Therefore, ocean temperatures and coastal land areas have more stable temperatures than inland areas.
  • Living things are made primarily of water. Consequently, they resist changes in temperature better than they would if composed of a liquid with a lower specific heat.
  • The transformation of a molecule from a liquid to a gas is called vaporization or evaporation.
  • This occurs when the molecule moves fast enough to overcome the attraction of other molecules in the liquid.
  • Even in a low-temperature liquid (with low average kinetic energy), some molecules are moving fast enough to evaporate.
  • Heating a liquid increases the average kinetic energy and increases the rate of evaporation.
  • Heat of vaporization is the quantity of heat that a liquid must absorb for 1 g of it to be converted from liquid to gas.
  • Water has a relatively high heat of vaporization, requiring about 580 cal of heat to evaporate 1 g of water at room temperature.
  • This is double the heat required to vaporize the same quantity of alcohol or ammonia.
  • This is because hydrogen bonds must be broken before a water molecule can evaporate from the liquid.
  • Water’s high heat of vaporization moderates climate.
  • Much of the sun’s heat absorbed by tropical oceans is used for evaporation of surface water.
  • As moist tropical air moves to the poles, water vapor condenses to form rain, releasing heat.
  • As a liquid evaporates, the surface of the liquid that remains behind cools, a phenomenon called evaporative cooling.
  • This occurs because the most energetic molecules are the most likely to evaporate, leaving the lower–kinetic energy molecules behind.
  • Evaporative cooling moderates temperature in lakes and ponds.
  • Evaporation of sweat in mammals or evaporation of water from the leaves of plants prevents terrestrial organisms from overheating.
  • Evaporation of water from the leaves of plants or the skin of humans removes excess heat.
  • Oceans and lakes don’t freeze solid because ice floats.
  • Water is unusual because it is less dense as a solid than as a cold liquid.
  • Most materials contract as they solidify, but water expands.
  • At temperatures above 4°C, water behaves like other liquids, expanding as it warms and contracting as it cools.
  • Water begins to freeze when its molecules are no longer moving vigorously enough to break their hydrogen bonds.
  • When water reaches 0°C, water becomes locked into a crystalline lattice, with each water molecule bonded to a maximum of four partners.
  • As ice starts to melt, some of the hydrogen bonds break, and water molecules can slip closer together than they can while in the ice state.
  • Ice is about 10% less dense than water at 4°C.
  • Therefore, ice floats on the cool water below.
  • This oddity has important consequences for life.
  • If ice sank, eventually all ponds, lakes, and even the ocean would freeze solid.
  • During the summer, only the upper few centimeters of the ocean would thaw.
  •  Instead, the surface layer of ice insulates liquid water below, preventing it from freezing and allowing life to exist under the frozen surface.
  • Water is the solvent of life.
  • A liquid that is a completely homogeneous mixture of two or more substances is called a solution.
  • A sugar cube in a glass of water will eventually dissolve to form a uniform solution of sugar and water.
  • The dissolving agent is the solvent, and the substance that is dissolved is the solute.
  •  In our example, water is the solvent and sugar is the solute.
  • In an aqueous solution, water is the solvent.
  • Water is not a universal solvent, but it is very versatile because of the polarity of water molecules.
  • °         Water is an effective solvent because it readily forms hydrogen bonds with charged and polar covalent molecules.
  • °         For example, when a crystal of salt (NaCl) is placed in water, the Na+ cations interact with the partial negative charges of the oxygen regions of water molecules.
  • °         The Cl− anions interact with the partial positive charges of the hydrogen regions of water molecules.
  • ·         Each dissolved ion is surrounded by a sphere of water molecules, a hydration shell.
  • ·         Eventually, water dissolves all the ions, resulting in a solution with two solutes: sodium and chloride ions.
  • ·         Polar molecules are also soluble in water because they form hydrogen bonds with water.
  • ·         Even large molecules, like proteins, can dissolve in water if they have ionic and polar regions.
  • ·         Any substance that has an affinity for water is hydrophilic (water-loving).
  • °         These substances are dominated by ionic or polar bonds.
  • ·         Some hydrophilic substances do not dissolve because their molecules are too large.
  • °         For example, cotton is hydrophilic because cellulose, its major constituent, has numerous polar covalent bonds. However, its giant cellulose molecules are too large to dissolve in water.
  • °         Water molecules form hydrogen bonds with the cellulose fibers of cotton, allowing you to dry yourself with your cotton towel as the water is pulled into the towel.
  • ·         Substances that have no affinity for water are hydrophobic (water-fearing).
  • °         These substances are nonionic and have nonpolar covalent bonds.
  • °         Because there are no consistent regions with partial or full charges, water molecules cannot form hydrogen bonds with hydrophobic molecules.
  • °         Oils such as vegetable oil are hydrophobic because the dominant bonds, carbon-carbon and carbon-hydrogen, share electrons equally.
  • °         Hydrophobic molecules are major ingredients of cell membranes.
  • ·         Biological chemistry is “wet” chemistry with most reactions involving solutes dissolved in water.
  • ·         Chemical reactions depend on collisions of molecules and therefore on the concentrations of solutes in aqueous solution.
  • ·         We measure the number of molecules in units called moles.
  • ·         The actual number of molecules in a mole is called Avogadro’s number, 6.02 × 1023.
  • ·         A mole is equal to the molecular weight of a substance but scaled up from daltons to grams.
  • ·         To illustrate, how could we measure out a mole of table sugar—sucrose (C12H22O11)?
  • °         A carbon atom weighs 12 daltons, hydrogen 1 dalton, and oxygen 16 daltons.
  • °         One molecule of sucrose would weigh 342 daltons, the sum of weights of all the atoms in sucrose, or the molecular weight of sucrose.
  • °         To get one mole of sucrose, we would weigh out 342 g.
  • ·         The advantage of using moles as a measurement is that a mole of one substance has the same number of molecules as a mole of any other substance.
  • °         If substance A has a molecular weight of 10 daltons and substance B has a molecular weight of 100 daltons, then we know that 10 g of substance A has the same number of molecules as 100 g of substance B.
  • °         A mole of sucrose contains 6.02 × 1023 molecules and weighs 342 g, while a mole of ethyl alcohol (C2H6O) also contains 6.02 × 1023 molecules but weighs only 46 g because the molecules are smaller.
  • °         Measuring in moles allows scientists to combine substances in fixed ratios of molecules.
  • ·         In “wet” chemistry, we are typically combining solutions or measuring the quantities of materials in aqueous solutions.
  • °         The concentration of a material in solution is called its molarity.
  • °         A one molar solution has one mole of a substance dissolved in one liter of solvent, typically water.
  • °         To make a 1 molar (1M) solution of sucrose, we would slowly add water to 342 g of sucrose until the total volume was 1 liter and all the sugar was dissolved.

Concept 3.3 Dissociation of water molecules leads to acidic and basic conditions that affect living organisms

  • ·         Occasionally, a hydrogen atom participating in a hydrogen bond between two water molecules shifts from one molecule to the other.
  • °         The hydrogen atom leaves its electron behind and is transferred as a single proton—a hydrogen ion (H+).
  • °         The water molecule that lost the proton is now a hydroxide ion (OH−).
  • °         The water molecule with the extra proton is now a hydronium ion (H3O+).
  • ·         A simplified way to view this process is to say that a water molecule dissociates into a hydrogen ion and a hydroxide ion:
  • °         H2O <=> H+ + OH−
  • ·         This reaction is reversible.
  • ·         At equilibrium, the concentration of water molecules greatly exceeds that of H+ and OH−.
  • ·         In pure water, only one water molecule in every 554 million is dissociated.
  • °         At equilibrium, the concentration of H+ or OH− is 10−7M (at 25°C).
  • ·         Although the dissociation of water is reversible and statistically rare, it is very important in the chemistry of life.
  • ·         Because hydrogen and hydroxide ions are very reactive, changes in their concentrations can drastically affect the chemistry of a cell.
  • ·         Adding certain solutes, called acids and bases, disrupts the equilibrium and modifies the concentrations of hydrogen and hydroxide ions.
  • ·         The pH scale is used to describe how acidic or basic a solution is.
  •  Organisms are sensitive to changes in pH.
  • ·         An acid is a substance that increases the hydrogen ion concentration in a solution.
  • °         When hydrochloric acid is added to water, hydrogen ions dissociate from chloride ions: HCl -> H+ + Cl−
  • °         Addition of an acid makes a solution more acidic.
  • ·         Any substance that reduces the hydrogen ion concentration in a solution is a base.
  • ·         Some bases reduce the H+ concentration directly by accepting hydrogen ions.
  • °         Ammonia (NH3) acts as a base when the nitrogen’s unshared electron pair attracts a hydrogen ion from the solution, creating an ammonium ion (NH4+).
  • °         NH3 + H+ <=> NH4+
  • ·         Other bases reduce H+ indirectly by dissociating to OH−, which then combines with H+ to form water.
  • °         NaOH -> Na+ + OH−                OH− + H+ -> H2O
  • ·         Solutions with more OH− than H+ are basic solutions.
  • ·         Solutions with more H+ than OH− are acidic solutions.
  • ·         Solutions in which concentrations of OH− and H+ are equal are neutral solutions.
  • ·         Some acids and bases (HCl and NaOH) are strong acids or bases.
  • °         These molecules dissociate completely in water.
  • ·         Other acids and bases (NH3) are weak acids or bases.
  • °         For these molecules, the binding and release of hydrogen ions are reversible.
  • °         At equilibrium, there will be a fixed ratio of products to reactants.
  • °         Carbonic acid (H2CO3) is a weak acid:
  • §         H2CO3 <=> HCO3− + H+
  • §         At equilibrium, 1% of the H2CO3 molecules will be dissociated.
  • ·         In any solution, the product of the H+ and OH− concentrations is constant at 10−14.
  • ·         Brackets ([H+] and [OH−]) indicate the molar concentration of the enclosed substance.
  • °         [H+] [OH−] = 10−14
  • °         In a neutral solution, [H+] = 10−7 M and [OH−] = 10−7 M
  • ·         Adding acid to a solution shifts the balance between H+ and OH− toward H+ and leads to a decline in OH−.
  • °         If [H+] = 10−5 M, then [OH−] = 10−9 M
  • °         Hydroxide concentrations decline because some of the additional acid combines with hydroxide to form water.
  • ·         Adding a base does the opposite, increasing OH− concentration and lowering H+ concentration.
  • ·         The H+ and OH− concentrations of solutions can vary by a factor of 100 trillion or more.
  • ·         To express this variation more conveniently, the H+ and OH− concentrations are typically expressed via the pH scale.
  • °         The pH scale, ranging from 1 to 14, compresses the range of concentrations by employing logarithms.
  • °         pH = − log [H+] or [H+] = 10−pH
  • °         In a neutral solution, [H+] = 10−7 M, and the pH = 7.
  • ·         Values for pH decline as [H+] increase.
  • ·         While the pH scale is based on [H+], values for [OH−] can be easily calculated from the product relationship.
  • ·         The pH of a neutral solution is 7.
  • ·         Acidic solutions have pH values less than 7, and basic solutions have pH values greater than 7.
  • ·         Most biological fluids have pH values in the range of 6 to 8.
  • °         However, the human stomach has strongly acidic digestive juice with a pH of about 2.
  • ·         Each pH unit represents a tenfold difference in H+ and OH− concentrations.
  • °         A small change in pH actually indicates a substantial change in H+ and OH− concentrations.
  • ·         The chemical processes in the cell can be disrupted by changes to the H+ and OH− concentrations away from their normal values, usually near pH 7.
  • ·         To maintain cellular pH values at a constant level, biological fluids have buffers.
  • ·         Buffers resist changes to the pH of a solution when H+ or OH− is added to the solution.
  • °         Buffers accept hydrogen ions from the solution when they are in excess and donate hydrogen ions when they have been depleted.
  • °         Buffers typically consist of a weak acid and its corresponding base.
  • °         One important buffer in human blood and other biological solutions is carbonic acid, which dissociates to yield a bicarbonate ion and a hydrogen ion.
  • °         The chemical equilibrium between carbonic acid and bicarbonate acts as a pH regulator. The equilibrium shifts left or right as other metabolic processes add or remove H+ from the solution.
  • Acid precipitation threatens the fitness of the environment.
  • ·         Acid precipitation is a serious assault on water quality in some industrialized areas.
  • °         Uncontaminated rain has a slightly acidic pH of 5.6.
  • °         The acid is a product of the formation of carbonic acid from carbon dioxide and water.
  • ·         Acid precipitation occurs when rain, snow, or fog has a pH that is more acidic than 5.6.
  • ·         Acid precipitation is caused primarily by sulfur oxides and nitrogen oxides in the atmosphere.
  • °         These molecules react with water to form strong acids that fall to the surface with rain or snow.
  • ·         The major source of these oxides is the burning of fossil fuels (coal, oil, and gas) in factories and automobiles.
  • ·         The presence of tall smokestacks allows this pollution to spread from its site of origin to contaminate relatively pristine areas thousands of kilometers away.
  • °         In 2001, rain in the Adirondack Mountains of upstate New York had an average pH of 4.3.
  • ·         The effects of acids in lakes and streams are more pronounced in the spring during snowmelt.
  • °         As the surface snows melt and drain down through the snowfield, the meltwater accumulates acid and brings it into lakes and streams all at once.
  • °         The pH of early meltwater may be as low as 3.
  • ·         Acid precipitation has a great impact on the eggs and the early developmental stages of aquatic organisms that are abundant in the spring.
  • ·         Thus, strong acidity can alter the structure of molecules and impact ecological communities.
  • ·         Direct impacts of acid precipitation on forests and terrestrial life are more controversial.
  • ·         However, acid precipitation can impact soils by affecting the solubility of soil minerals.
  • °         Acid precipitation can wash away key soil buffers and plant nutrients such as calcium and magnesium ions.
  • °         It can also increase the concentrations of compounds such as aluminum to toxic levels.
  • °         This has done major damage to forests in Europe and substantial damage of forests in North America.
  • °         Progress has been made in reducing acid precipitation.

 

 

Chapter 3 – Water Objectives

 

 

Chapter 3   Water & the Fitness of the Environment
Objectives
The Properties of Water

1.        With the use of a diagram or diagrams, explain why water molecules are:

a.         polar

b.         capable of hydrogen bonding with four neighboring water molecules

2.        List four characteristics of water that are emergent properties resulting from hydrogen bonding.

3.        Define cohesion and adhesion. Explain how water’s cohesion and adhesion contribute to the movement of water from the roots to the leaves of a tree.

4.        Distinguish between heat and temperature, using examples to clarify your definitions.

5.        Explain the following observations by referring to the properties of water:

n                      Coastal areas have milder climates than adjacent inland areas.

n                      Ocean temperatures fluctuate much less than air temperatures on land.

n                      Insects like water striders can walk on the surface of a pond without breaking the surface.

n                      If you slightly overfill a water glass, the water will form a convex surface above the top of the glass.

n                      If you place a paper towel so that it touches spilled water, the towel will draw in the water.

n                      Ice floats on water.

n                      Humans sweat and dogs pant to cool themselves on hot days.

6.        Distinguish among a solute, a solvent, and a solution.

7.        Distinguish between hydrophobic and hydrophilic substances.

8.        Explain how you would make up a one molar (1M) solution of ethyl alcohol.

The Dissociation of Water Molecules

9.        Name the products of the dissociation of water and give their concentration in pure water.

10.       Define acid, base, and pH.

11.       Explain how acids and bases may directly or indirectly alter the hydrogen ion concentration of a solution.

12.       Using the bicarbonate buffer system as an example, explain how buffers work.

13.       Briefly explain the causes and effects of acid precipitation.

 

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Chapter 40 AP Intro to Systems Objectives

 

 

Chapter 40     Introduction to Animal Structure & Function
Objectives
Functional Animal Anatomy: An Overview
1. Define bioenergetics.
2. Distinguish between anatomy and physiology. Explain how functional anatomy relates to these terms.
Body Plans and the External Environment
3. Explain how physical laws constrain animal form.
4. Explain how the size and shape of an animal’s body affect its interactions with the environment.
5. Define tissue.
6. Distinguish among collagenous fibers, elastic fibers, and reticular fibers.
7. From micrographs or diagrams, correctly identify the following animal tissues, explain how their structure relates to their functions, and note examples of each type.
a. Epithelial tissue
b. Connective tissue
i.  Loose connective tissue
ii. Adipose tissue
iii. Fibrous connective tissue
iv. Cartilage
v.  Bone
vi. Blood
c. Muscle tissue
i.  Skeletal (striated) muscle
ii. Cardiac muscle
iii. Smooth muscle
d. Nervous tissue
i.  Neuron
Introduction to the Bioenergetics of Animals
8. Describe the basic sources of chemical energy and their fate in animal cells.
9. Define biosynthesis.
10. Define metabolic rate and explain how it can be determined for animals.
11. Distinguish between endothermic and exothermic animals.
12. Describe the relationship between metabolic rate and body size.
13. Distinguish between basal metabolic rate and standard metabolic rate. Describe the major factors that influence energy requirements.
14. Describe the natural variations found in the energy strategies of endotherms and ectotherms.
Regulating the Internal Environment
15. Distinguish between regulators and conformers for a particular environmental variable.
16. Define homeostasis. Describe the three functional components of a homeostatic control system.
17. Distinguish between positive and negative feedback mechanisms.
18. Define thermoregulation. Explain in general terms how endotherms and ectotherms manage their heat budgets.
19. Name four physical processes by which animals exchange heat with their environment.
20. Discuss the role of hair, feathers, and adipose tissue in insulation.
21. Explain the role of vasoconstriction and vasodilation in modifying the transfer of body heat with the environment.
22. Describe animal adaptations to facilitate evaporative cooling.
23. Describe thermoregulatory mechanisms utilized by endothermic invertebrates.
24. Explain how ectotherms and endotherms may acclimatize to changing environmental temperatures.
25. Explain the role of heat-shock proteins in helping cells to cope with severe temperature changes.
26. Define torpor, hibernation, estivation, and daily torpor.

 

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