**Molecular Genetics: Problem 1**

Genotypes:

A man with hemophilia is XhY where h = hemophilia gene and H = the normal gene.

Any daughter with normal phenotype whose father has hemophilia will be a carrier.

Her genotype must be:

**XhXH and NOT XHXH**

**daughter**x

**normal man**

**XhXH**x

**XHY**

A. If the daughter marries a normal male the probability of a daughter having hemophilia is **zero**.

B. About **50%** **of male children** would have hemophilia (Boxes 2 and 4 above)

C. The probability that all 4 sons have inherited hemophilia would be: 1/2 x 1/2 x 1/2 x 1/2 or **1/16**.

**BACK**