| Chapter 26 Early Earth & the Origin of Life | ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
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| Chapter 26 Early Earth & the Origin of Life | ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
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| Chapter 14 Mendel & the Gene Idea | ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
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| Chapter 15 Chromosomal Basis of Heredity | |
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| Relating Mendelian Inheritance to the Behavior of Chromosomes 1. Explain how the observations of cytologists and geneticists provided the basis for the chromosome theory of inheritance. 2. Explain why Drosophila melanogaster is a good experimental organism for genetic studies. 3. Explain why linked genes do not assort independently. 4. Distinguish between parental and recombinant phenotypes. 5. Explain how crossing over can unlink genes. 6. Explain how Sturtevant created linkage maps. 7. Define a map unit. 8. Explain why Mendel did not find linkage between seed color and flower color, despite the fact that these genes are on the same chromosome. 9. Explain how genetic maps are constructed for genes located far apart on a chromosome. 10. Explain the effect of multiple crossovers between loci. 11. Explain what additional information cytogenetic maps provide. Sex Chromosomes 12. Describe how sex is genetically determined in humans and explain the significance of the SRY gene. 13. Distinguish between linked genes and sex-linked genes. 14. Explain why sex-linked diseases are more common in human males. 15. Describe the inheritance patterns and symptoms of color blindness, Duchenne muscular dystrophy, and hemophilia. 16. Describe the process of X inactivation in female mammals. Explain how this phenomenon produces the tortoiseshell coloration in cats. Errors and Exceptions in Chromosomal Inheritance 17. Explain how nondisjunction can lead to aneuploidy. 18. Define trisomy, triploidy, and polyploidy. Explain how these major chromosomal changes occur and describe possible consequences. 19. Distinguish among deletions, duplications, inversions, and translocations. 20. Describe the type of chromosomal alterations responsible for the following human disorders: Down syndrome, Klinefelter syndrome, extra Y, triple-X syndrome, Turner syndrome, cri du chat syndrome, and chronic myelogenous leukemia. 21. Define genomic imprinting. Describe the evidence that suggests that the Igf2 gene is maternally imprinted. 22. Explain why extranuclear genes are not inherited in a Mendelian fashion. |
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Experiment 3. (Frequency/Distance between T and S)
Determine the recombination frequency for the genes controlling Tallness and Snout:
| 40 tall-upturned snout | = 40% | expected |
| 42 dwarf-downturned snout | = 42% | expected |
| 9 dwarf-upturned snout | = 9% | recombinant |
| 9 tall-downturned snout | = 9% | recombinant |
Total = 100%
Therefore this recombination frequency between genes T and S is 18%
One can determine the relative frequency between genes using the percent frequencies as distances.
The Recombinant relationships from experiments 1-3 are:
Exp. 1 T-A = 12 map units Exp. 2 A-S = 5 map units Exp. 3 T-S = 18 map units
An arrangement that fits the data would be:
This individual probably is XXX.
The individual is a female. Nondisjunction of sex chromosomes produces a variety of aneuploid conditions in humans. Most of these conditions appear to upset genetic balance less than aneuploid conditions involving autosomes. Extra copies of the X chromosome are deactivated as Barr bodies in the somatic cells. Females with trisomy of the X chromosome (XXX), which occurs about once in approximately 1000 live births, are healthy and cannot be distinguished from XX females except by karyotype.
An Example of nondisjunction:
Klinefelter’s syndrome
49 ,XXXXY |
This karyotype shows a variant of Klinefelter’s syndrome.
Individuals with this syndrome are male, typically with the karyotype 47,XXY. Individuals with Klinefelter’s syndrome exhibit a characteristic phenotype including tall stature, infertility, gynecomastia and hypogonadism. Aneuploidy above one extra chromosome is usually fatal but because of X-inactivation, which “turns off” all but one X chromosome per cell, the effects of 3 extra chromosomes are reduced. |