Pumpkin Decorating Contest

 

Pumpkin Decorating Contest
Sponsored by SHS Biology Club

 

Rules:
  Any Club, group, or individuals may enter one or more decorated pumpkins
Cost to enter a pumpkin is $3.00 (pay to Ms. Massengale)
Pumpkins may be painted but not cut
Decorated pumpkins must be set up in the library by Monday, October 26

Prizes:
Winning club, group, or individuals will be awarded a cash prize collected from the $3.00 entry fee
  An article with picture will be published in the newspaper & school annual for the winning group

Judging:
   The Biology Club will judge the pumpkins before school on October 27

 

 

Prentice Hall Chapter Openers

 

Prentice Hall Chapter Openers

 

Chapter 1 – Science of Biology

#1  #2  #3  #4  #5
#6  #7  #8  #9  #10

Chapter 12 – DNA and RNA

#1   #2   #3   #4   #5
#6   #7   #8   #9   #10
#11  #12  #13  #14  #15

Chapter 23 – Roots, Stems, and Leaves

#1  #2  #3  #4  #5
#6  #7  #8  #9  #10

Chapter 2 – Chemistry of Life

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#6   #7   #8   #9   #10
#11  #12  #13  #14  #15

Chapter 13 – Genetic Engineering

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#6  #7  #8  #9  #10

Chapter 24 – Reproduction of Seed Plants

#1  #2  #3  #4  #5
#6  #7  #8  #9  #10

Chapter 3 – Biosphere

#1  #2  #3  #4  #5
#6  #7  #8  #9  #10

Chapter 14 – Human Genome

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#6  #7  #8  #9  #10

Chapter 25 – Plant Responses & Adaptations

#1  #2  #3  #4  #5
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Chapter 4 – Ecosystems & Communities

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#6  #7  #8  #9  #10

Chapter 15 – Darwin’s Theory of Evolution

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Chapter 26 – Sponges and Cnidarians

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Chapter 5 – Populations

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Chapter 16 – Evolution of populations

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Chapter 27 – Worms and Mollusks

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Chapter 6 – Humans in the Biosphere

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Chapter 17 – History of Life

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Chapter 28 – Arthropods and Echinoderms

#1  #2  #3  #4  #5
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Chapter 7 – Cell Structure and Function

#1     #2    #3   #4   #5
#6    #7    #8   #9   #10
#11   #12   #13  #14  #15

Chapter 18 – Classification

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Chapter 29 – Comparing Invertebrates

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Chapter 8 – Photosynthesis

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Chapter 19 – Bacteria and Viruses

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Chapter 30 – Fish and Amphibians

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Chapter 9 – Cellular Respiration

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Chapter 20 – Protists

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Chapter 31 – Reptiles and Birds

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Chapter 10 – Cell Growth and Division

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Chapter 21 – Fungi

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Chapter 32 – Mammals

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Chapter 11 -Introduction to Genetics

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Meiosis
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Chapter 22 – Plant Diversity

#1  #2  #3  #4  #5
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Chapter 33 – Comparing Chordates

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Chapter 34 Animal Behavior

#1  #2  #3  #4  #5
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Chapter 1 The Science of Life

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Probability Notes Bi

 

Probability

 

Probability Facts:

  • Probability is the likelihood that an event will occur from random chance  
  • Probabilities are always between 0 and 1
  • Probabilities can be written as fractions, decimals or percentages
  • All possible events together must have a probability of 1
  • The probability that an event will not occur is 0
  • To find the probability of a particular event, we use this formula:

 

Number of successful events
(where a successful event is the result that you are looking )
Probability of an event = ———————————————
Total number of events

 

  • Whenever a coin is flipped, there is a 50% chance of getting heads & a 50% chance of getting tails.
  • The chance of inheriting one of two alleles from a parent is also 50%

Applying Probability to Mendel’s Peas:

  • During the late 1850’s, Gregor Mendel used the general rules of probability to explain the basic principles of heredity by breeding green peas in planned experiments
  • Different versions of genes are called alleles
  • For most genes, two alleles exist
  • If an organism has two different alleles for the same gene, the dominant allele will be expressed in the phenotype of the organism, while the recessive allele will not
  • Each parent will pass on one of its two alleles

Probability Laws:

  • The Law of Multiplication or Product Rule states that the chance of two or more independent events occurring together is the product of the probability of the events occurring separately
    Example: The chance of inheriting a specific allele from one parent & another allele from the other parent is 1/2  x  1/2 or 1/4
  • The following table shows the probability of the offspring genotypes whenever two heterozygous parents are crossed:

 

Parents     Rr  x  Rr
Offpring  RR 1/2  x  1/2  = 1/4
Offpring  Rr 1/2  x  1/2  = 1/4
Offpring   r r 1/2  x  1/2  = 1/4

Complete the following table for crossing 2 Homozygous parents: 

 

Parents     RR  x  rr
Offpring  Rr  

 

Click here for the correct answer

Example 1
Imagine we are rolling a fair dice. There are six equally likely outcomes: 1, 2, 3, 4, 5 and 6.

  1. What is the probability of getting a five?
    In this case there is only one successful outcome or event, 5.

 

Number of successful events
Probability of a five = ———————————————
Total number of events
     1
Probability of a five = ———-
     6

 

  1. What is the probability of getting an even number?
    In this case there are 3 successful outcomes, which are 2, 4 and 6.

 

Number of successful outcomes
Probability of an even number = ————————————
Total number of outcomes
     3
Probability of an even number = ———-
     6
     1
Probability of an even number = ———-
     2

 

Therefore the probability of getting an even number when rolling a dice is 50% or 1/2.

  • Now apply these numbers to the dihybrid cross RrYy  x  RrYy Probability of being R_ Y_ is 3/4 x 3/4 = 9/16  Probability of being R_ y_ is 3/4 x 1/4 = 3/16  Probability of being r_Y_ is 1/4 x 3/4 = 3/16 Probability of being r ryy is 1/4 x 1/4 = 1/16 This matches our 9:3:3:1 phenotypic ratio.

Example Problem:

Work a trihybrid cross of heterozygous parents   —    RrYyGg   x   RrYyGg

  1. What is the probability of having a dominant gene for all three traits?
  2. What is the probability of being recessive for all three traits?
  3. What is the probability of being dominant for 2 and recessive for one?
  4. What is the probability of being dominant for 1 and recessive for two?

Click here for the correct answers

  • The Law of Addition is used when considering the probability of either of two mutually exclusive events
  • The individual probabilities of the 2 exclusive events are added
    Example:
    The probability of selecting the three of clubs or any ace from the deck is the sum of the individual probabilities:  Probability of selecting a three of clubs = 1/52
    Probability of selecting any ace = 4/52
    Total probability = 1/52 + 4/52 = 5/52