DNA Quiz 2

Name: 

Mendel’s Genetics

 

 

True/False
Indicate whether the sentence or statement is true or false.
1.
The law of segregation states that two or more pairs of alleles separate independently of one
another during gamete formation.
2.
Cells that contain a single set of chromosomes are said to be haploid (N).
3.
Crosses involving a study of one gene are called monohybrid crosses.
4.
A dominant allele masks the effect of a recessive allele.
5.
Mendel concluded that the patterns of inheritance are determined entirely by the environment.
6.
A Punnett square represents the phenotype of an organism.
7.
The physical appearance of an individual organism, as determined by the genes it has inherited from its parents, is called its genotype.
8.
Individuals must exhibit a trait in order for it to appear in their offspring.
9.
In codominance, two alleles are expressed at the same time.
 

Multiple Choice
Identify the letter of the choice that best completes the statement or answers the question.
10.
In fruit flies, the gene for long wings, L, is dominant to the gene for short wings, l.  A heterozygous long wing male and a short wing female produce many offspring. The possible genotype(s) among the long-winged offspring is (are)
a.
Ll only
c.
LL and Ll
b.
ll only
d.
Ll and ll.
11.
In drosophila, curled wing is recessive to straight wing. If a homozygous straight-winged fly is mated with a curled-wing fly, how many different phenotypes will be produced?
a.
1
c.
3
b.
2
d.
4
12.
If an organism has two identical alleles for a trait, it is
a.
homozygous.
c.
homozygous dominant.
b.
heterozygous.
d.
heterozygous recessive.
13.
Alleles for the same trait separate during
a.
fertilization.
c.
meiosis I.
b.
mitosis.
d.
meiosis II.
14.
The inheritance of genes that determine one trait (hair color) is not affected by the inheritance of genes that control another trait (tongue rolling).  Which of Mendel’s rules apply to the above statement?
a.
the rule of dominance
c.
the rule of independent assortment
b.
the rule of segregation
15.
In fruit flies, the gene for straight wings, C, is dominant to the gene for curly wings, c. Two flies, when bred, produced 98 straight-winged and 102 curly-winged offspring.  What was the genotype of the curly-winged offspring?
a.
CC
c.
cc
b.
Cc
d.
straight-winged
16.
All homozygous individuals have:
a.
the same genotype
c.
two alleles exactly alike
b.
the same phenotype
d.
a hybrid genotype.
17.
If a family has three daughters, the probability that the next child will be a girl is
a.
1/4.
c.
1/2.
b.
1/3.
d.
3/4.
18.
Mendel explained the reappearance of recessive traits in the F2 generation in his principle of
a.
independent assortment.
c.
dominance.
b.
segregation.
d.
blending inheritance.
19.
If any offspring from a test cross show a recessive phenotype, the parent with the unknown genotype is
a.
heterozygous dominant.
c.
heterozygous recessive.
b.
homozygous dominant.
d.
homozygous recessive.
20.
A homozygous black rabbit is mated with a heterozygous rabbit. If black is dominant over white, they should produce:
a.
all white rabbits
b.
all black rabbits
c.
half black and half white rabbits
d.
one pure dominant and heterozygous individual.
21.
Mendel’s finding that the inheritance of one trait had no effect on the inheritance of another became known as the
a.
law of dominance.
c.
law of segregation.
b.
law of universal inheritance.
d.
law of independent assortment.
22.
The phenotype of an organism
a.
represents its genetic composition.
b.
reflects all the traits that are actually expressed.
c.
occurs only in dominant pure organisms.
d.
cannot be seen.
23.
In humans the ability to taste PTC paper is dominant to non-tasting and hair color shows incomplete dominance (Dark hair x blond hair => brown hair).  A brown haired man who cannot taste PTC paper marries a woman with brown hair and who can taste PTC paper.  Their first child had brown hair and could not taste PTC paper. What are the chances that their next child will be a brown taster?
a.
1/4
c.
1/8
b.
1/2
d.
3/8
24.
Two long-furred cats were mated and produced 25 percent short-furred cats.  The parents were probably:
a.
pure recessive individuals
b.
pure dominant individuals
c.
heterozygous individuals
d.
one pure dominant and heterozygous individual.
25.
When certain types of black roosters are crossed with white hens, speckled chickens result. These chickens, which have a mixture of black and white feathers, show
a.
dominance.
c.
polygenes.
b.
codominance.
d.
recessive
26.
codominance : both traits are displayed::
a.
probability : crosses
c.
homozygous : alleles are same
b.
heterozygous : alleles are the same
d.
Punnett square : chromosomes combine
27.
A Punnett square is used to determine the
a.
probable outcome of a cross.
c.
result of segregation.
b.
actual outcome of a cross.
d.
result of meiosis I.
28.
If a family has four sons, the probability that the next child will be a boy is
a.
1/2.
c.
1/5.
b.
1/4.
d.
4/5.
29.
Suppose that on Mars green creatures are dominant over red creatures and that 3-eyes are recessive to 4-eyes.  Assume that inheritance of traits on Mars occurs the same way as on Earth.  A cross between 2 GgEe Martians would result in what fraction of the offspring being red-3-eyed Martians?
a.
1/16
c.
4/16
b.
2/16
d.
9/16
30.
The fact that a man and woman, both of whom have wavy hair, could have children with curly hair, wavy hair, or straight hair is best explained by the phenomenon called
a.
codominance.
b.
dominance.
c.
incomplete dominance.
d.
None of the above; this would be impossible.
31.
A Punnett square does not show the
a.
genetic makeup of the eggs.
c.
genetic makeup of the sperm.
b.
probable outcome of a cross.
d.
actual outcome of a cross.
32.
The “father” of genetics was
a.
T. A. Knight.
c.
Gregor Mendel.
b.
Dr. Judd.
d.
None of the above
33.
What is the probability that the offspring of a homozygous dominant individual and a  homozygous recessive individual will exhibit the dominant phenotype?
a.
0.25
c.
0.66
b.
0.5
d.
1.0
34.
Which of the following is the designation for Mendel’s original pure strains of plants?
a.
P
c.
F1
b.
P1
d.
F2
35.
F2 : F1 ::
a.
P : F1
c.
F1 : P
b.
F1 : F2
d.
dominant trait : recessive trait
36.
The passing of traits from parents to offspring is called
a.
genetics.
c.
development.
b.
heredity.
d.
maturation.
37.
homozygous : heterozygous ::
a.
heterozygous : Bb
c.
dominant : recessive
b.
probability : predicting chances
d.
homozygous : BB
38.
The phenotype of an organism
a.
represents its genetic composition.
b.
reflects all the traits that are actually expressed.
c.
occurs only in dominant pure organisms.
d.
cannot be seen.
39.
If an individual has two recessive alleles for the same trait, the individual is said to be
a.
homozygous for the trait.
c.
heterozygous for the trait.
b.
haploid for the trait.
d.
mutated.
40.
Tallness (T) is dominant to shortness (t) in pea plants. Which of the following represents a genotype of a pea plant that is heterozygous for tallness?
a.
T
c.
Tt
b.
TT
d.
tt
41.
How many different phenotypes can be produced by a pair of codominant alleles?
a.
1
c.
3
b.
2
d.
4
chp_9_web_tutorial_files/i0440000.jpg
42.
Refer to the illustration above. The genotype represented by the cell labeled “2” is
a.
GgIi.
c.
GI.
b.
GGIi.
d.
Gi.
In rabbits, black fur (B) is dominant to brown fur (b). Consider the following cross between two rabbits.
      chp_9_web_tutorial_files/i0460000.jpg
43.
Refer to the illustration above. Both of the parents in the cross are
a.
black.
c.
homozygous dominant.
b.
brown.
d.
homozygous recessive.
44.
Refer to the illustration above. The genotypic ratio of the F1 generation would be
a.
1:1.
c.
1:3.
b.
3:1.
d.
1:2:1.
45.
In pea plants, yellow seeds are dominant over green seeds. What would be the expected genotype ratio in a cross between a plant with green seeds and a plant that is heterozygous for seed color?
a.
1:3
c.
4:1
b.
1:2:1
d.
1:1

 

Check Your Work     Reset

Chromatography Lab

Chromatography Lab

Problem:  How do you separate the different pigments in a plant?

Materials:

Cone-type (size 4) coffee filter paper (or Whatman #1 chromatography paper)
large glass jars
acetone
distilled water
capillary tubes
fresh spinach
mortar and pestle
clean sand

Introduction:

In this activity you will be experimenting with a technique called chromatography which will allow you to visually demonstrate that the pigment in leaves is a combination of several different colored pigments.

This technique is useful in that it can separate and identify the various components of mixtures, such as those contained in plant pigments. A pigment is a substance that absorbs light at specific wavelengths, chlorophyll is one of these pigments. Its green-yellow in color is due to the absorption of red, orange, blue, and violet wavelengths and the reflection of the green and yellow wavelengths.   This occurs when white light (containing all of the light wavelengths, or the entire spectrum of colors) shines on the leaf surface, all of the wavelengths are absorbed except for the ones you see, which are green-yellow, those are the portions of the spectrum being reflected.

If the conditions are identical, the relative distance moved by a particular compound is the same from one mixture to another. This is why chromatography can be used to identify a compound. The actual identification requires a simple calculation as shown below:

Rf = distance moved by compound from original spot divided by the distance moved by solvent from original spot

It is important to remember that several factors can influence the reliability of the Rf value, these include humidity, temperature, solvent, pigment extract preparation, and the amounts of the material present.  Values are comparable only when the extracts are prepared in the same way and the chromatograms are prepared identically and developed together in the same container.

Acetone is flammable (even the amount found in nail polish remover), keep it away from sparks or open flames. Wear eye protection, especially if using pure acetone.

Procedure

1.   Each lab group (or individual if not working in groups) will need 4 strips of filter paper, approximately 6 inches long and 1 inch wide, 2 chromatography development containers (500 ml beakers or large fruit jars work well), 2 large rubber bands (able to stretch around the vessels from the mouth to the bottom of the vessel), 2 solvents, water and either pure acetone, or nail polish remover.

2.   Do the following with both fresh spinach leaves; tear leaf material and place in a glass container, cover with acetone (this should be done the day before the actual lab activity). An alternative pigment extraction technique is to use a
mortar and pestle. Place plant material the vessel, add a little clean sand, some acetone and then grind until a dark green liquid appears.    Both techniques yield very dark pigments with which to work. Be certain to keep the pigments apart throughout the entire activity.

3.   Place one of each solvents (water and acetone, or nail polish remover) in the chromatography vessels and stretch a rubber band length-wise around each vessel. The rubber band will be the mechanism for hanging the chromatography strips.

4.   Make a pencil mark on each of the 2 chromatography strips, in the center, directly above the point of the strip, about 1 inch from the tip of the paper. Using a capillary tube, or tooth pick, apply the plant pigment to each filter paper strip. This is done by touching the tooth pick or capillary tube which has been dipped in the pigment, to the pencil mark. Make an application, then wave the paper gently to dry it a little before the next application. Be patient, you will need 12 to 15 applications.

5.   By now you should have 2 strips with spinach pigment.  Suspend one of each in each of the chromatography development vessels. You can attach them with paper clips, or simply fold over a portion of the end and it should hang in place. The tip of each strip should just touch the solvent.

6.   Wait 20 to 30 minutes for the chromatograms to develop. Remove the chromatograms. Mark with a pencil (NOT a pen) where the solvent stopped as it moved up the chromatogram. This is called the solvent front. Mark also where each pigment stopped moving up the chromatogram. Using the equation below, determine a reference number for each pigment on the chromatograms. Depending on which chromatogram you are viewing, you should see greens, yellow/yellow orange, and red. All measurements should be in mm. (Any material which did not move from the
pencil dot is insoluble).

Rf = distance moved by compound from original spot divided by the
distance moved by solvent from original spot

Note: each pigment has a special name,
green = chlorophyll a or b
yellow/yellow orange = carotene
red = anthocyanin
brown = xanthophyll

The reference numbers for the chlorophylls in this activity are:
0.28 = chlorophyll a, 0.18 = chlorophyll b (spinach). You need these
numbers so that you can determine one chlorophyll from the other.
Calculate reference fronts for all of your pigments.

See if your calculations come close to those above for chlorophyll a and b.

Note:  You can use different solvents such as mixtures involving petroleum ether
to do this sort of paper chromatography.

To view notes and a graphic showing a separation of plant pigments involving
paper chromatography, click here.  Can you calculate the Rf values for the
pigments separated in this graphic?

Conclusion Questions

1.  What reference numbers (Rf) did you calculate for chlorophyll a and chlorophyll b?
2.  With what you have discovered about pigments, what conclusions can you
make regarding the changing color of leaves in autumn?
3.  What adaptive purpose do different colored pigments serve for a plant?
4.  Why do some pigments move farther up the chromatogram than others?
5.  What are some possible sources of error in this lab?

Paper chromatography is a technique used to separate a mixture into its component molecules. The molecules migrate, or move up the paper, at different rates because of differences in solubility, molecular mass, and hydrogen bonding with the paper.

For a simple, beautiful example of this technique, draw a large circle in the center of a piece of filter paper with a black water-soluble, felt-tip pen. Fold the paper into a cone and place the tip in a container of water. In just a few minutes you will have tie-dyed filter paper!

Separation of black ink pigments

The green, blue, red, and lavender colors that came from the black ink should help you to understand that what appears to be a single color may in fact be a material composed of many different pigments —and such is the case with chloroplasts.

chromatography setup

 

In paper chromatography the pigments are dissolved in a solvent that carries them up the paper. In the ink example, the solvent is water. To separate the pigments of the chloroplasts, you must use an organic solvent

 

 

pigment separation

 

pigment separation

 

Analysis of Results I

If you did a number of chromatographic separations, each for a different length of time, the pigments would migrate a different distance on each run. However, the migration of each pigment relative to the migration of the solvent would not change. This migration of pigment relative to migration of solvent is expressed as a constant, Rf (Reference front). It can be calculated by using the formula:

 

Chromatography of Plant Pigments 3

 

 

Chromatography of Plant Pigments

 

 

Introduction:

 

Can chromatography be used to separate mixtures of chemical substances? The purpose of this experiment is to answer this question. In paper chromatography, a liquid sample flows down a vertical strip of absorbent paper, on which the components of a mixture are deposited in specific directions and locations. Chromatography is a tool used to examine and separate mixtures of chemical substances. Chromatography is essential to the separation of pure substances from complex mixtures. Separation results in a chromatographically pure substance. Chromatography allows you to determine the properties of chemical substances.

The relationship between the chromatography paper, mixture, and the solvent is very important in all chromatographic separations. The solvent has to dissolve the mixture that should be separated. The paper must also absorb the components of the mixtures selectively and reversibly. The substances making up the mixture must be evenly dispersed in the water. Chromatography is a simple and inexpensive tool for separating and identifying chemical mixtures if all these things are done.

 

Hypothesis:

 

Paper can be used to separate mixed chemicals.

 

Materials:

 

The materials used in this lab are filter paper, test tube, rubber stopper, paper clip, metric ruler, black felt-tip pen, pencil, calculator, and water.

 

Methods:

 

First, bend a paper clip so that it’s straight with a hook at one end. Push the straight end of the paper clip into the bottom of a cork stopper. Then, hang a thin strip of filter paper on the hooked end of the paper clip and insert the paper strip into the test tube. The paper should not touch the sides and should almost touch the bottom of the test tube. Next, remove the paper strip from the test tube. Now draw a solid 5-mm-wide band about 25 mm from the bottom of the paper, using a black felt tip pen. After this, use a pencil to draw a line across the paper strip 10 cm above the black band. Then, put the filter paper back into the test tube with the bottom of the paper in the water and the black band above the water. Observe what happens as the liquid travels up the paper and record the changes you see. When the solvent has reached the pencil line, remove the paper from the test tube. Let the paper dry on the desk. Finally, with a metric ruler, measure the distances from the starting point to the top edge of each color. Record the data in a data table and calculate a ratio for each color by dividing the distance, the color traveled by the distance the solvent traveled.

 

Results:

 

The results of the chromatography experiment are shown in a chart and a graph.

 

Color of ink (list in order) Distance traveled by each color (mm) Distance solvent traveled (mm) Ratio traveled = distance color moved divided by distance solvent moved
Yellow 70 108 0.65
Orange  

85

 

108

 

0.79

Pink 95  

108

 

0.88

Violet 102  

108

 

0.94

Blue 108  

108

 

1.00

 

 

 

Questions:

1. How many colors separated from the black ink? Five colors separated from the ink: yellow, orange, pink, violet, and blue.

 

2. What served as the solvent for the ink? Water served as the solvent for the ink.

 

3. As the solvent traveled up the paper, which color of ink appeared first? Dark blue appeared first.

 

4. List the colors in order from top to bottom that separated from the black ink? The colors separated in the order of: blue, violet, pink, orange, and yellow.

 

5. In millimeters, how far did the solvent travel? The solvent traveled 108 mm.

 

6. From your results, what can you conclude is true about black ink? Black ink is a mixture of several different colors.

 

7. Why did the inks separate? The inks separated because black ink is a mixture of different pigments that are soluble in water, have different molecular characteristics, and travel different distances.

 

8. Why did some inks move a greater distance? Some inks move a greater distance because molecules in ink have different characteristics, like how readily they are absorbed by paper. This means that the ink least readily absorbed by paper will travel farthest from the starting mark and the ink most readily absorbed by paper will be the closest to the starting mark. All of the different color inks that were separated were different in how readily they are absorbed by paper.

Error Analysis:

 

There are a few errors that could have changed the results. First, there could be inaccurate measurements of how far every color traveled or how far the water traveled up the filter paper. Another error could occur when calculating the ratio traveled, Rf value. Also, a longer test tube could have been used by different groups which would make the filter strip longer. This means that a group could have detected another color because they had more room on their filter paper. This also could have affected the ratios. Finally, the groups could have put different amounts of black ink on the filter paper.

 

Conclusion:

 

The hypothesis that paper can be used to separate mixed chemicals was correct. The different colored inks mixed together give the black its color. The five colors that separated from the black ink were blue, violet, pink, orange, and yellow. Blue appeared first and then was followed by violet, pink, orange, and yellow. The colors separated the way they did because they have different molecular characteristics, like how readily they were absorbed by the paper and their solubility in water. Blue was most readily absorbed by the paper and soluble by water, while yellow was the least.

BACK

 

Chromatography of Simulated Plant Pigments

 

Chromatography of Simulated Plant Pigments

 

Introduction
    This experiment is conducted to investigate the components Plant Pigments separating visibly. There are a couple of different types of components in plant pigments, and they became clearly visible during this lab. The most important and abundant chemical pigment found in plants is chlorophyll. This pigment exists in two forms; chlorophyll a and chlorophyll b. Chlorophyll absorbs two main colors from light quite well. These are blue, and red. The chlorophyll reflects green light very well, however, the two different types of chlorophyll have their maximum absorption at different wavelengths of light. Chlorophyll a, being the main photosynthetic pigment, has a primary purpose to convert light energy to chemical energy used by the plant itself. Chlorophyll b absorbs light in a region of the spectrum apart from the dominant chlorophyll, and transfers the energy it produces to chlorophyll a. Along with chlorophyll b in transferring their energy produced to the dominant chlorophyll, two other pigments that are found in plants are carotenes and xanthophylls, which are orange and yellow respectively. Since chlorophyll is such a dominant pigment in green plants, this domination hides the color of the carotenes and xanthophylls in the leaves. This causes most plant leaves to appear green most of the time. During the autumn, however, the chlorophyll starts to break down, causing the carotenes and xanthophylls to show their bright red, orange and yellow colors.
These brilliant colors can be separated another way. This different technique, known as paper chromatography, separates mixtures in a liquid into individual components. The technique is based on the fact that each substance in a mixture has a specific affinity for a solid surface and a specific solubility in different solvents. By this method, the solid surface is the cellulose fibers in the chromatography paper, and the solvent is the solution that was placed in the bottom of the developing chamber.
This separation takes place through a process of absorption and capillary action. Just a small drop of the mixture, in this case plant pigment to be separated, is placed at the bottom of the strip of chromatography paper. The chromatography paper is then placed in the developing chamber with a solvent, which wicks up the paper, pulling the solvent up the paper by capillary action, and the mixture of pigments is dissolved as the solvent passes over it. The different components of the mixture move upward at different rates. A compound with greater solubility will travel farther than one with less solubility. The pigments then show up as color streaks on the chromatography paper. These substances have formed a pattern called a chromatogram on the chromatography paper.
The Rf values for each pigment is calculated to establish the relative rate of migration for each pigment. This value represents the ratio of the distance a pigment traveled on the chromatogram relative to the distance the solvent front moved.
Scientists use the Rf value of a sample to identify the molecule. Any molecule in a given solvent matrix system has a uniquely consistent Rf value. The formula for this value is as follows:

Rf = Distance each pigment traveled ¸ Distance solvent front traveled

 

Hypothesis
    Using paper chromatography, the pigments that give a leaf its color can be separated and observed to determine the Rf value of each pigment and their function during photosynthesis.

 

Materials
For this experiment the following items are used — one chromatography reaction chamber, one paper chromatography strip, one capillary pipette, a pencil and paper, calculator, ruler, 50 ml beaker, colored pencils, approximately 10 ml of solvent depending on the size of the reaction chamber, scissors, and simulated plant pigment.

 

Procedure
Use scissors to cut the bottom of the chromatography paper to a tapered end. Measure the strip and cut the length to equal slightly longer than the reaction chamber. Draw a faint pencil line at the bottom of the tapered end and use a capillary pipette to add some simulated plant pigment to this line. Add 5-10 ml of solvent to the reaction chamber. Extend the chromatography strip through the slit in the lids of the reaction chamber and carefully lower the strip into the chamber so the tapered end is in the solvent and the pencil line is above the solvent level. Make sure the strip does not touch the walls of the chamber and do not bump the chamber as the pigments begin to separate. After the pigments have completely separated and the solvent front has reached the top of the chamber, remove the strip and mark the solvent front with a pencil line before it evaporates. Measure and record the distance the solvent and each pigment traveled. Use a calculator to determine the Rf values for each pigment.

 

Data

 

Table 1

Band # Pigment Color Migration distance (mm) Rf value
1 Carotene Orange 59mm .94
2 Xanthophyll Yellow 56mm .89
3 Chlorophyll a Light green 29mm .46
4 Chlorophyll b Dark green 14mm .22
Solvent 63mm

Questions
1. Describe what happened to the original spot of simulated plant pigments?
  The solvent separated  the original spot by wicking up the solvent while dissolving the various pigments in the spot.
2. List some other uses of chromatography?  Chromatography can be used to separate various mixtures of subtances, liquids and gases.
3. Which of the 4 pigments migrated the furthest and why?  carotene ( orange) because it was the most soluble in the solvent
4. Which type of chlorophyll was the most soluble?  chlorophyll a
5. Explain why leaves change color in the fall?  In Autumn, chlorophyll starts to break down which allows the other brilliant plant pigment colors to show. These pigments include the red, orange, and yellow colors.
6. What is the function of plant pigments in photosynthesis?  Plant pigments trap light energy and convert it into chemical energy that can be used by the plant to make glucose or sugar.

Error Analysis
The chromatography paper touched the sides of the chamber during the waiting time which caused the migration to go slightly to the side instead of straight to the top. Also the strip was bent at the top so there could have been a slight error in measuring the migration of the solvent  front.

Conclusion
Paper chromatography proved to be an accurate method of separating and observing the various colors of plant pigments. The pigments dissolved in the solvent and migrated upward. The colors were observed and their migration distances measured & recorded. The
Rf value of each pigment was determined by dividing its migration by the migration of the solvent.  It was determined that 4 pigments were present in the original spot — carotene, xanthophyll, chlorophyll a, and chlorophyll b. Carotene was the most soluble, while chlorophyll b was the least soluble.

Chapter 6 – A Tour of the Cell Lecture Outline

Chapter 6    A Tour of the Cell    Lecture Outline

Overview: The Importance of Cells

·         All organisms are made of cells.

°         Many organisms are single-celled.

°         Even in multicellular organisms, the cell is the basic unit of structure and function.

·         The cell is the simplest collection of matter that can live.

·         All cells are related by their descent from earlier cells.

A. How We Study Cells

1. Microscopes provide windows to the world of the cell.

·         The discovery and early study of cells progressed with the invention of microscopes in 1590 and their improvement in the 17th century.

·         In a light microscope (LM), visible light passes through the specimen and then through glass lenses.

°         The lenses refract light such that the image is magnified into the eye or onto a video screen.

·         Microscopes vary in magnification and resolving power.

°         Magnification is the ratio of an object’s image to its real size.

°         Resolving power is a measure of image clarity.

§         It is the minimum distance two points can be separated and still be distinguished as two separate points.

§         Resolution is limited by the shortest wavelength of the radiation used for imaging.

·         The minimum resolution of a light microscope is about 200 nanometers (nm), the size of a small bacterium.

·         Light microscopes can magnify effectively to about 1,000 times the size of the actual specimen.

°         At higher magnifications, the image blurs.

·         Techniques developed in the 20th century have enhanced contrast and enabled particular cell components to be stained or labeled so they stand out.

·         While a light microscope can resolve individual cells, it cannot resolve much of the internal anatomy, especially the organelles.

·         To resolve smaller structures, we use an electron microscope (EM), which focuses a beam of electrons through the specimen or onto its surface.

°         Because resolution is inversely related to wavelength used, electron microscopes (whose electron beams have shorter wavelengths than visible light) have finer resolution.

°         Theoretically, the resolution of a modern EM could reach 0.002 nanometer (nm), but the practical limit is closer to about 2 nm.

·         Transmission electron microscopes (TEMs) are used mainly to study the internal ultrastructure of cells.

°         A TEM aims an electron beam through a thin section of the specimen.

°         The image is focused and magnified by electromagnets.

°         To enhance contrast, the thin sections are stained with atoms of heavy metals.

·         Scanning electron microscopes (SEMs) are useful for studying surface structures.

°         The sample surface is covered with a thin film of gold.

°         The beam excites electrons on the surface of the sample.

°         These secondary electrons are collected and focused on a screen.

°         The result is an image of the topography of the specimen.

°         The SEM has great depth of field, resulting in an image that seems three-dimensional.

·         Electron microscopes reveal organelles that are impossible to resolve with the light microscope.

°         However, electron microscopes can only be used on dead cells.

·         Light microscopes do not have as high a resolution, but they can be used to study live cells.

·         Microscopes are major tools in cytology, the study of cell structures.

·         Cytology combined with biochemistry, the study of molecules and chemical processes in metabolism, to produce modern cell biology.

2. Cell biologists can isolate organelles to study their functions.

·         The goal of cell fractionation is to separate the major organelles of the cells so their individual functions can be studied.

·         This process is driven by an ultracentrifuge, a machine that can spin at up to 130,000 revolutions per minute and apply forces of more than 1 million times gravity (1,000,000 g).

·         Fractionation begins with homogenization, gently disrupting the cell.

·         The homogenate is spun in a centrifuge to separate heavier pieces into the pellet while lighter particles remain in the supernatant.

°         As the process is repeated at higher speeds and for longer durations, smaller and smaller organelles can be collected in subsequent pellets.

·         Cell fractionation prepares isolates of specific cell components.

·         This enables the functions of these organelles to be determined, especially by the reactions or processes catalyzed by their proteins.

°         For example, one cellular fraction was enriched in enzymes that function in cellular respiration.

°         Electron microscopy revealed that this fraction is rich in mitochondria.

°         This evidence helped cell biologists determine that mitochondria are the site of cellular respiration.

·         Cytology and biochemistry complement each other in correlating cellular structure and function.

B. A Panoramic View of the Cell

1. Prokaryotic and eukaryotic cells differ in size and complexity.

·         All cells are surrounded by a plasma membrane.

·         The semifluid substance within the membrane is the cytosol, containing the organelles.

·         All cells contain chromosomes that have genes in the form of DNA.

·         All cells also have ribosomes, tiny organelles that make proteins using the instructions contained in genes.

·         A major difference between prokaryotic and eukaryotic cells is the location of chromosomes.

·         In a eukaryotic cell, chromosomes are contained in a membrane-enclosed organelle, the nucleus.

·         In a prokaryotic cell, the DNA is concentrated in the nucleoid without a membrane separating it from the rest of the cell.

·         In eukaryote cells, the chromosomes are contained within a membranous nuclear envelope.

·         The region between the nucleus and the plasma membrane is the cytoplasm.

°         All the material within the plasma membrane of a prokaryotic cell is cytoplasm.

·         Within the cytoplasm of a eukaryotic cell are a variety of membrane-bound organelles of specialized form and function.

°         These membrane-bound organelles are absent in prokaryotes.

·         Eukaryotic cells are generally much bigger than prokaryotic cells.

·         The logistics of carrying out metabolism set limits on cell size.

°         At the lower limit, the smallest bacteria, mycoplasmas, are between 0.1 to 1.0 micron.

°         Most bacteria are 1–10 microns in diameter.

°         Eukaryotic cells are typically 10–100 microns in diameter.

·         Metabolic requirements also set an upper limit to the size of a single cell.

·         As a cell increases in size, its volume increases faster than its surface area.

°         Smaller objects have a greater ratio of surface area to volume.

·         The plasma membrane functions as a selective barrier that allows the passage of oxygen, nutrients, and wastes for the whole volume of the cell.

·         The volume of cytoplasm determines the need for this exchange.

·         Rates of chemical exchange across the plasma membrane may be inadequate to maintain a cell with a very large cytoplasm.

·         The need for a surface sufficiently large to accommodate the volume explains the microscopic size of most cells.

·         Larger organisms do not generally have larger cells than smaller organisms—simply more cells.

·         Cells that exchange a lot of material with their surroundings, such as intestinal cells, may have long, thin projections from the cell surface called microvilli. Microvilli increase surface area without significantly increasing cell volume.

2. Internal membranes compartmentalize the functions of a eukaryotic cell.

·         A eukaryotic cell has extensive and elaborate internal membranes, which partition the cell into compartments.

·         These membranes also participate directly in metabolism, as many enzymes are built into membranes.

·         The compartments created by membranes provide different local environments that facilitate specific metabolic functions, allowing several incompatible processes to go on simultaneously in a cell.

·         The general structure of a biological membrane is a double layer of phospholipids.

·         Other lipids and diverse proteins are embedded in the lipid bilayer or attached to its surface.

·         Each type of membrane has a unique combination of lipids and proteins for its specific functions.

°         For example, enzymes embedded in the membranes of mitochondria function in cellular respiration.

C. The Nucleus and Ribosomes

1. The nucleus contains a eukaryotic cell’s genetic library.

·         The nucleus contains most of the genes in a eukaryotic cell.

°         Additional genes are located in mitochondria and chloroplasts.

·         The nucleus averages about 5 microns in diameter.

·         The nucleus is separated from the cytoplasm by a double membrane called the nuclear envelope.

°         The two membranes of the nuclear envelope are separated by 20–40 nm.

°         The envelope is perforated by pores that are about 100 nm in diameter.

°         At the lip of each pore, the inner and outer membranes of the nuclear envelope are fused to form a continuous membrane.

°         A protein structure called a pore complex lines each pore, regulating the passage of certain large macromolecules and particles.

·         The nuclear side of the envelope is lined by the nuclear lamina, a network of protein filaments that maintains the shape of the nucleus.

·         There is evidence that a framework of fibers called the nuclear matrix extends through the nuclear interior.

·         Within the nucleus, the DNA and associated proteins are organized into discrete units called chromosomes, structures that carry the genetic information.

·         Each chromosome is made up of fibrous material called chromatin, a complex of proteins and DNA.

°         Stained chromatin appears through light microscopes and electron microscopes as a diffuse mass.

·         As the cell prepares to divide, the chromatin fibers coil up and condense, becoming thick enough to be recognized as the familiar chromosomes.

·         Each eukaryotic species has a characteristic number of chromosomes.

°         A typical human cell has 46 chromosomes.

°         A human sex cell (egg or sperm) has only 23 chromosomes.

·         In the nucleus is a region of densely stained fibers and granules adjoining chromatin, the nucleolus.

°         In the nucleolus, ribosomal RNA (rRNA) is synthesized and assembled with proteins from the cytoplasm to form ribosomal subunits.

°         The subunits pass through the nuclear pores to the cytoplasm, where they combine to form ribosomes.

·         The nucleus directs protein synthesis by synthesizing messenger RNA (mRNA).

°         The mRNA travels to the cytoplasm through the nuclear pores and combines with ribosomes to translate its genetic message into the primary structure of a specific polypeptide.

2. Ribosomes build a cell’s proteins.

·         Ribosomes, containing rRNA and protein, are the organelles that carry out protein synthesis.

°         Cell types that synthesize large quantities of proteins (e.g., pancreas cells) have large numbers of ribosomes and prominent nucleoli.

·         Some ribosomes, free ribosomes, are suspended in the cytosol and synthesize proteins that function within the cytosol.

·         Other ribosomes, bound ribosomes, are attached to the outside of the endoplasmic reticulum or nuclear envelope.

°         These synthesize proteins that are either included in membranes or exported from the cell.

·         Ribosomes can shift between roles depending on the polypeptides they are synthesizing.

D. The Endomembrane System

·         Many of the internal membranes in a eukaryotic cell are part of the endomembrane system.

·         These membranes are either directly continuous or connected via transfer of vesicles, sacs of membrane.

°         In spite of these connections, these membranes are diverse in function and structure.

°         The thickness, molecular composition and types of chemical reactions carried out by proteins in a given membrane may be modified several times during a membrane’s life.

·         The endomembrane system includes the nuclear envelope, endoplasmic reticulum, Golgi apparatus, lysosomes, vacuoles, and the plasma membrane.

1. The endoplasmic reticulum manufactures membranes and performs many other biosynthetic functions.

·         The endoplasmic reticulum (ER) accounts for half the membranes in a eukaryotic cell.

·         The ER includes membranous tubules and internal, fluid-filled spaces called cisternae.

·         The ER membrane is continuous with the nuclear envelope, and the cisternal space of the ER is continuous with the space between the two membranes of the nuclear envelope.

·         There are two connected regions of ER that differ in structure and function.

°         Smooth ER looks smooth because it lacks ribosomes.

°         Rough ER looks rough because ribosomes (bound ribosomes) are attached to the outside, including the outside of the nuclear envelope.

·         The smooth ER is rich in enzymes and plays a role in a variety of metabolic processes.

°         Enzymes of smooth ER synthesize lipids, including oils, phospholipids, and steroids.

°         These include the sex hormones of vertebrates and adrenal steroids.

°         In the smooth ER of the liver, enzymes help detoxify poisons and drugs such as alcohol and barbiturates.

§         Frequent use of these drugs leads to the proliferation of smooth ER in liver cells, increasing the rate of detoxification.

§         This increases tolerance to the target and other drugs, so higher doses are required to achieve the same effect.

°         Smooth ER stores calcium ions.

§         Muscle cells have a specialized smooth ER that pumps calcium ions from the cytosol and stores them in its cisternal space.

§         When a nerve impulse stimulates a muscle cell, calcium ions rush from the ER into the cytosol, triggering contraction.

§         Enzymes then pump the calcium back, readying the cell for the next stimulation.

·         Rough ER is especially abundant in cells that secrete proteins.

°         As a polypeptide is synthesized on a ribosome attached to rough ER, it is threaded into the cisternal space through a pore formed by a protein complex in the ER membrane.

°         As it enters the cisternal space, the new protein folds into its native conformation.

°         Most secretory polypeptides are glycoproteins, proteins to which a carbohydrate is attached.

°         Secretory proteins are packaged in transport vesicles that carry them to their next stage.

·         Rough ER is also a membrane factory.

°         Membrane-bound proteins are synthesized directly into the membrane.

°         Enzymes in the rough ER also synthesize phospholipids from precursors in the cytosol.

°         As the ER membrane expands, membrane can be transferred as transport vesicles to other components of the endomembrane system.

2. The Golgi apparatus is the shipping and receiving center for cell products.

·        Many transport vesicles from the ER travel to the Golgi apparatus for modification of their contents.

·         The Golgi is a center of manufacturing, warehousing, sorting, and shipping.

·         The Golgi apparatus is especially extensive in cells specialized for secretion.

·         The Golgi apparatus consists of flattened membranous sacs—cisternae—looking like a stack of pita bread.

°         The membrane of each cisterna separates its internal space from the cytosol.

°         One side of the Golgi, the cis side, is located near the ER. The cis face receives material by fusing with transport vesicles from the ER.

°         The other side, the trans side, buds off vesicles that travel to other sites.

·         During their transit from the cis to the trans side, products from the ER are usually modified.

·         The Golgi can also manufacture its own macromolecules, including pectin and other noncellulose polysaccharides.

·         The Golgi apparatus is a very dynamic structure.

°         According to the cisternal maturation model, the cisternae of the Golgi progress from the cis to the trans face, carrying and modifying their protein cargo as they move.

·         Finally, the Golgi sorts and packages materials into transport vesicles.

°         Molecular identification tags are added to products to aid in sorting.

°         Products are tagged with identifiers such as phosphate groups. These act like ZIP codes on mailing labels to identify the product’s final destination.

3. Lysosomes are digestive compartments.

·         A lysosome is a membrane-bound sac of hydrolytic enzymes that an animal cell uses to digest macromolecules.

·         Lysosomal enzymes can hydrolyze proteins, fats, polysaccharides, and nucleic acids.

·         These enzymes work best at pH 5.

°         Proteins in the lysosomal membrane pump hydrogen ions from the cytosol into the lumen of the lysosomes.

°         Rupture of one or a few lysosomes has little impact on a cell because the lysosomal enzymes are not very active at the neutral pH of the cytosol.

°         However, massive rupture of many lysosomes can destroy a cell by autodigestion.

·         Lysosomal enzymes and membrane are synthesized by rough ER and then transferred to the Golgi apparatus for further modification.

·         Proteins on the inner surface of the lysosomal membrane are spared by digestion by their three-dimensional conformations, which protect vulnerable bonds from hydrolysis.

·         Lysosomes carry out intracellular digestion in a variety of circumstances.

·         Amoebas eat by engulfing smaller organisms by phagocytosis.

°         The food vacuole formed by phagocytosis fuses with a lysosome, whose enzymes digest the food.

°         As the polymers are digested, monomers pass to the cytosol to become nutrients for the cell.

·         Lysosomes can play a role in recycling of the cell’s organelles and macromolecules.

°         This recycling, or autophagy, renews the cell.

°         During autophagy, a damaged organelle or region of cytosol becomes surrounded by membrane.

°         A lysosome fuses with the resulting vesicle, digesting the macromolecules and returning the organic monomers to the cytosol for reuse.

·         The lysosomes play a critical role in the programmed destruction of cells in multicellular organisms.

°         This process plays an important role in development.

°         The hands of human embryos are webbed until lysosomes digest the cells in the tissue between the fingers.

°         This important process is called programmed cell death, or apoptosis.

4. Vacuoles have diverse functions in cell maintenance.

·         Vesicles and vacuoles (larger versions) are membrane-bound sacs with varied functions.

°         Food vacuoles are formed by phagocytosis and fuse with lysosomes.

°         Contractile vacuoles, found in freshwater protists, pump excess water out of the cell to maintain the appropriate concentration of salts.

°         A large central vacuole is found in many mature plant cells.

§         The membrane surrounding the central vacuole, the tonoplast, is selective in its transport of solutes into the central vacuole.

§         The functions of the central vacuole include stockpiling proteins or inorganic ions, disposing of metabolic byproducts, holding pigments, and storing defensive compounds that defend the plant against herbivores.

§         Because of the large vacuole, the cytosol occupies only a thin layer between the plasma membrane and the tonoplast. The presence of a large vacuole increases surface area to volume ratio for the cell.

E. Other Membranous Organelles

1. Mitochondria and chloroplasts are the main energy transformers of cells.

·         Mitochondria and chloroplasts are the organelles that convert energy to forms that cells can use for work.

·         Mitochondria are the sites of cellular respiration, generating ATP from the catabolism of sugars, fats, and other fuels in the presence of oxygen.

·         Chloroplasts, found in plants and algae, are the sites of photosynthesis.

°         They convert solar energy to chemical energy and synthesize new organic compounds such as sugars from CO2 and H2O.

·         Mitochondria and chloroplasts are not part of the endomembrane system.

°         In contrast to organelles of the endomembrane system, each mitochondrion or chloroplast has two membranes separating the innermost space from the cytosol.

°         Their membrane proteins are not made by the ER, but rather by free ribosomes in the cytosol and by ribosomes within the organelles themselves.

·         Both organelles have small quantities of DNA that direct the synthesis of the polypeptides produced by these internal ribosomes.

·         Mitochondria and chloroplasts grow and reproduce as semiautonomous organelles.

·         Almost all eukaryotic cells have mitochondria.

°         There may be one very large mitochondrion or hundreds to thousands of individual mitochondria.

°         The number of mitochondria is correlated with aerobic metabolic activity.

°         A typical mitochondrion is 1–10 microns long.

°         Mitochondria are quite dynamic: moving, changing shape, and dividing.

·         Mitochondria have a smooth outer membrane and a convoluted inner membrane with infoldings called cristae.

°         The inner membrane divides the mitochondrion into two internal compartments.

°         The first is the intermembrane space, a narrow region between the inner and outer membranes.

°         The inner membrane encloses the mitochondrial matrix, a fluid-filled space with DNA, ribosomes, and enzymes.

°         Some of the metabolic steps of cellular respiration are catalyzed by enzymes in the matrix.

°         The cristae present a large surface area for the enzymes that synthesize ATP.

·         The chloroplast is one of several members of a generalized class of plant structures called plastids.

°         Amyloplasts are colorless plastids that store starch in roots and tubers.

°         Chromoplasts store pigments for fruits and flowers.

°         Chloroplasts contain the green pigment chlorophyll as well as enzymes and other molecules that function in the photosynthetic production of sugar.

·         Chloroplasts measure about 2 microns × 5 microns and are found in leaves and other green organs of plants and algae.

·         The contents of the chloroplast are separated from the cytosol by an envelope consisting of two membranes separated by a narrow intermembrane space.

·         Inside the innermost membrane is a fluid-filled space, the stroma, in which float membranous sacs, the thylakoids.

°         The stroma contains DNA, ribosomes, and enzymes.

°         The thylakoids are flattened sacs that play a critical role in converting light to chemical energy. In some regions, thylakoids are stacked like poker chips into grana.

°         The membranes of the chloroplast divide the chloroplast into three compartments: the intermembrane space, the stroma, and the thylakoid space.

·         Like mitochondria, chloroplasts are dynamic structures.

°         Their shape is plastic, and they can reproduce themselves by pinching in two.

·         Mitochondria and chloroplasts are mobile and move around the cell along tracks of the cytoskeleton.

2. Peroxisomes generate and degrade H2O2 in performing various metabolic functions.

·         Peroxisomes contain enzymes that transfer hydrogen from various substrates to oxygen.

°         An intermediate product of this process is hydrogen peroxide (H2O2), a poison.

°         The peroxisome contains an enzyme that converts H2O2 to water.

°         Some peroxisomes break fatty acids down to smaller molecules that are transported to mitochondria as fuel for cellular respiration.

°         Peroxisomes in the liver detoxify alcohol and other harmful compounds.

°         Specialized peroxisomes, glyoxysomes, convert the fatty acids in seeds to sugars, which the seedling can use as a source of energy and carbon until it is capable of photosynthesis.

·         Peroxisomes are bound by a single membrane.

·         They form not from the endomembrane system, but by incorporation of proteins and lipids from the cytosol.

·         They split in two when they reach a certain size.

F. The Cytoskeleton

·         The cytoskeleton is a network of fibers extending throughout the cytoplasm.

·         The cytoskeleton organizes the structures and activities of the cell.

1. The cytoskeleton provides support, motility, and regulation.

·         The cytoskeleton provides mechanical support and maintains cell shape.

·         The cytoskeleton provides anchorage for many organelles and cytosolic enzymes.

·         The cytoskeleton is dynamic and can be dismantled in one part and reassembled in another to change the shape of the cell.

·         The cytoskeleton also plays a major role in cell motility, including changes in cell location and limited movements of parts of the cell.

·         The cytoskeleton interacts with motor proteins to produce motility.

°         Cytoskeleton elements and motor proteins work together with plasma membrane molecules to move the whole cell along fibers outside the cell.

°         Motor proteins bring about movements of cilia and flagella by gripping cytoskeletal components such as microtubules and moving them past each other.

°         The same mechanism causes muscle cells to contract.

·         Inside the cell, vesicles can travel along “monorails” provided by the cytoskeleton.

·         The cytoskeleton manipulates the plasma membrane to form food vacuoles during phagocytosis.

·         Cytoplasmic streaming in plant cells is caused by the cytoskeleton.

·         Recently, evidence suggests that the cytoskeleton may play a role in the regulation of biochemical activities in the cell.

·         There are three main types of fibers making up the cytoskeleton: microtubules, microfilaments, and intermediate filaments.

·         Microtubules, the thickest fibers, are hollow rods about 25 microns in diameter and 200 nm to 25 microns in length.

°         Microtubule fibers are constructed of the globular protein tubulin.

°         Each tubulin molecule is a dimer consisting of two subunits.

°         A microtubule changes in length by adding or removing tubulin dimers.

·         Microtubules shape and support the cell and serve as tracks to guide motor proteins carrying organelles to their destination.

·         Microtubules are also responsible for the separation of chromosomes during cell division.

·         In many cells, microtubules grow out from a centrosome near the nucleus.

°         These microtubules resist compression to the cell.

·         In animal cells, the centrosome has a pair of centrioles, each with nine triplets of microtubules arranged in a ring.

°         Before a cell divides, the centrioles replicate.

·         A specialized arrangement of microtubules is responsible for the beating of cilia and flagella.

°         Many unicellular eukaryotic organisms are propelled through water by cilia and flagella.

°         Cilia or flagella can extend from cells within a tissue layer, beating to move fluid over the surface of the tissue.

§         For example, cilia lining the windpipe sweep mucus carrying trapped debris out of the lungs.

·         Cilia usually occur in large numbers on the cell surface.

°         They are about 0.25 microns in diameter and 2–20 microns long.

·         There are usually just one or a few flagella per cell.

°         Flagella are the same width as cilia, but 10–200 microns long.

·         Cilia and flagella differ in their beating patterns.

°         A flagellum has an undulatory movement that generates force in the same direction as the flagellum’s axis.

°         Cilia move more like oars with alternating power and recovery strokes that generate force perpendicular to the cilium’s axis.

·         In spite of their differences, both cilia and flagella have the same ultrastructure.

°         Both have a core of microtubules sheathed by the plasma membrane.

°         Nine doublets of microtubules are arranged in a ring around a pair at the center. This “9 + 2” pattern is found in nearly all eukaryotic cilia and flagella.

°         Flexible “wheels” of proteins connect outer doublets to each other and to the two central microtubules.

°         The outer doublets are also connected by motor proteins.

°         The cilium or flagellum is anchored in the cell by a basal body, whose structure is identical to a centriole.

·         The bending of cilia and flagella is driven by the arms of a motor protein, dynein.

°         Addition and removal of a phosphate group causes conformation changes in dynein.

°         Dynein arms alternately grab, move, and release the outer microtubules.

°         Protein cross-links limit sliding. As a result, the forces exerted by the dynein arms cause the doublets to curve, bending the cilium or flagellum.

·         Microfilaments are solid rods about 7 nm in diameter.

°         Each microfilament is built as a twisted double chain of actin subunits.

°         Microfilaments can form structural networks due to their ability to branch.

·         The structural role of microfilaments in the cytoskeleton is to bear tension, resisting pulling forces within the cell.

·         They form a three-dimensional network just inside the plasma membrane to help support the cell’s shape, giving the cell cortex the semisolid consistency of a gel.

·         Microfilaments are important in cell motility, especially as part of the contractile apparatus of muscle cells.

°         In muscle cells, thousands of actin filaments are arranged parallel to one another.

°         Thicker filaments composed of myosin interdigitate with the thinner actin fibers.

°         Myosin molecules act as motor proteins, walking along the actin filaments to shorten the cell.

·         In other cells, actin-myosin aggregates are less organized but still cause localized contraction.

°         A contracting belt of microfilaments divides the cytoplasm of animal cells during cell division.

°         Localized contraction brought about by actin and myosin also drives amoeboid movement.

§         Pseudopodia, cellular extensions, extend and contract through the reversible assembly and contraction of actin subunits into microfilaments.

à       Microfilaments assemble into networks that convert sol to gel.

à       According to a widely accepted model, filaments near the cell’s trailing edge interact with myosin, causing contraction.

à       The contraction forces the interior fluid into the pseudopodium, where the actin network has been weakened.

à       The pseudopodium extends until the actin reassembles into a network.

·         In plant cells, actin-myosin interactions and sol-gel transformations drive cytoplasmic streaming.

°         This creates a circular flow of cytoplasm in the cell, speeding the distribution of materials within the cell.

·         Intermediate filaments range in diameter from 8–12 nanometers, larger than microfilaments but smaller than microtubules.

·         Intermediate filaments are a diverse class of cytoskeletal units, built from a family of proteins called keratins.

°         Intermediate filaments are specialized for bearing tension.

·         Intermediate filaments are more permanent fixtures of the cytoskeleton than are the other two classes.

·         They reinforce cell shape and fix organelle location.

G. Cell Surfaces and Junctions

1. Plant cells are encased by cell walls.

·         The cell wall, found in prokaryotes, fungi, and some protists, has multiple functions.

·         In plants, the cell wall protects the cell, maintains its shape, and prevents excessive uptake of water.

·         It also supports the plant against the force of gravity.

·         The thickness and chemical composition of cell walls differs from species to species and among cell types within a plant.

·         The basic design consists of microfibrils of cellulose embedded in a matrix of proteins and other polysaccharides. This is the basic design of steel-reinforced concrete or fiberglass.

·         A mature cell wall consists of a primary cell wall, a middle lamella with sticky polysaccharides that holds cells together, and layers of secondary cell wall.

·         Plant cell walls are perforated by channels between adjacent cells called plasmodesmata.

2. The extracellular matrix (ECM) of animal cells functions in support, adhesion, movement, and regulation.

·         Though lacking cell walls, animal cells do have an elaborate extracellular matrix (ECM).

·         The primary constituents of the extracellular matrix are glycoproteins, especially collagen fibers, embedded in a network of glycoprotein proteoglycans.

·         In many cells, fibronectins in the ECM connect to integrins, intrinsic membrane proteins that span the membrane and bind on their cytoplasmic side to proteins attached to microfilaments of the cytoskeleton.

°         The interconnections from the ECM to the cytoskeleton via the fibronectin-integrin link permit the integration of changes inside and outside the cell.

·         The ECM can regulate cell behavior.

°         Embryonic cells migrate along specific pathways by matching the orientation of their microfilaments to the “grain” of fibers in the extracellular matrix.

°         The extracellular matrix can influence the activity of genes in the nucleus via a combination of chemical and mechanical signaling pathways.

§         This may coordinate the behavior of all the cells within a tissue.

3. Intercellular junctions help integrate cells into higher levels of structure and function.

·         <BL1>Neighboring cells in tissues, organs, or organ systems often adhere, interact, and communicate through direct physical contact.

·         Plant cells are perforated with plasmodesmata, channels allowing cytosol to pass between cells.

°         Water and small solutes can pass freely from cell to cell.

°         In certain circumstances, proteins and RNA can be exchanged.

·         Animals have 3 main types of intercellular links: tight junctions, desmosomes, and gap junctions.

·         In tight junctions, membranes of adjacent cells are fused, forming continuous belts around cells.

°         This prevents leakage of extracellular fluid.

·         Desmosomes (or anchoring junctions) fasten cells together into strong sheets, much like rivets.

°         Intermediate filaments of keratin reinforce desmosomes.

·         Gap junctions (or communicating junctions) provide cytoplasmic channels between adjacent cells.

°         Special membrane proteins surround these pores.

°         Ions, sugars, amino acids, and other small molecules can pass.

°         In embryos, gap junctions facilitate chemical communication during development.

4. A cell is a living unit greater than the sum of its parts.

·         While the cell has many structures with specific functions, all these structures must work together.

°         For example, macrophages use actin filaments to move and extend pseudopodia to capture their bacterial prey.

°         Food vacuoles are digested by lysosomes, a product of the endomembrane system of ER and Golgi.

·         The enzymes of the lysosomes and proteins of the cytoskeleton are synthesized on the ribosomes.

·         The information for the proteins comes from genetic messages sent by DNA in the nucleus.

·         All of these processes require energy in the form of ATP, most of which is supplied by the mitochondria.

·         A cell is a living unit greater than the sum of its parts.