Insect

Insects   All Materials © Cmassengale  

Phylum Arthropoda        Subphylum Uniramia          Class Insecta

Characteristics

  • Largest arthropod group
  • Found in freshwater & terrestrial habitats, especially tropical areas
  • Legs, mouthparts, & antenna jointed
  • Body segmented into three sections — head, thorax, & abdomen
  • Six legs & up to two pairs of wings located on thorax
  • Have compound & simple eyes
  • One pair of antennae on head
  • Abdomen has 11 segments
  • Exoskeleton, covering & protecting body, is made of chitin & must be molted to grow
  • Elaborate mouthparts include:
         *  Mandibles – jaws
    *
       Maxillae – paired sensory structures that move food to mouth
      Labium – lower lip
      Labrum – upper lip
      Palpi – used for tasting
  • Known as mandibulates
  • Spiracles on abdomen open into tracheal tubes for oxygen & carbon dioxide exchange
  • Tympanic membranes on 1st abdominal segment aid in hearing
  • Thorax divided into 3 sections — prothorax, mesothorax, & metathorax
  • One pair of legs on each thoracic segment
  • Wings located on mesothorax & metathorax
  • Ovipositor located on the end of the abdomen in female insects & used to dig hole & lay eggs

Common Insect Orders

  • Orthoptera – grasshoppers, crickets, & cockroaches 2 pairs of straight wings & chewing mouthparts)
  • Isoptera – termites (feed on wood)
  • Dermaptera – earwigs (pincers on end of abdomen)
  • Anoplura – sucking lice (wingless parasites)
  • Hemiptera – true bugs (have triangular-shaped scutellum & last 1/3 of wings membranous)
  • Homoptera – aphids & cicadas (membranous wings held roof-like over body
  • Ephemeroptera – mayflies (have 2 cerci on tail, membranous wings, & nonfunctional mouthparts in adults)
  • Odonata – dragonflies & damselflies (2 pairs of equal size, membranous wings, strong fliers, feed on other insects)
  • Neuroptera – Dobson flies &  lacewings (2 pairs of membranous wings)
  • Coleoptera – beetles (hard forewings or elytra, membranous hindwings)
  • Lepidoptera – butterflies & moths (powdery scales covered wings
  • Diptera – flies & mosquitoes (one pair of wings, 2nd pair modified into balancing structure called halteres)
  • Siphonaptera – fleas (parasites on birds & mammals, wingless as adults)
  • Hymenoptera – bees, ants, & wasps (stinger on abdomen for protection, may live together in groups, pollinators)

     Click Here for Pictures of Insect Orders

 

Success of Insects

  • Found everywhere except in deep part of ocean
  • Very short life span & rapidly adapt to new environments
  • Small size helps minimize competition in habitats
  • Flight helps escape predators & move into other environments

Environmental Impact

  • Pollinate almost 2/3’s of all plants
  • Serve as food for fish, birds, & mammals
  • Help recycle materials (termites recycle wood)
  • Make useful byproducts such as silk & honey
  • Some spread disease
  • Agricultural pests

Grasshoppers

External Structure

  • Head with antenna, compound eyes, & chewing mouthparts
  • Walking legs on prothorax & mesothorax; jumping legs on metathorax
  • Tarsus are lower leg segments with spines, hooks, & pads
  • Leathery, protective forewings on mesothorax & membranous hindwings for flight on metathorax
  • Covering over thorax called pronotum

Internal Structure
Digestive & Excretory Systems

  • Cutting & chewing mouthparts (labium, labrum, mandibles, & maxillae)
  • Saliva added to food in mouth
  • Esophagus carries food to crop for temporary storage
  • Gizzard has chitinous plates to grind food
  • Midgut (insect’s stomach) has gastric caeca (pouches) to secrete digestive enzymes to break down food
  • Food is absorbed into the body cavity or coelom in the hindgut (composed of the colon & rectum)
  • Malpighian tubules filter chemical wastes from the blood & deposit them in the rectum where they leave through the anus

Circulatory System

  • Open circulation of blood
  • Aorta is the largest blood vessel carrying blood to the body cells
  • Hearts are muscular regions of the aorta in the posterior end of the abdomen that pump blood toward head
  • Blood flows back toward abdomen carrying digested food & re-enters the aorta through openings called ostia

Respiratory System

  • Air enters through openings called spiracles along the sides of the abdomen & enters into tracheal tubes that branch into smaller tracheoles where gas exchange with body cells occurs 
  • Tracheal tubes carry oxygen to body cells & return carbon dioxide to leave the body though spiracles

Nervous System

  • Simple brain, nerve cords, & ganglia 
  • Three simple eyes or ocelli (detect light) & a pair of compound eyes (can detect movement but not images)
  • Tympanic membrane on 1st abdominal segment
  • Pair of antenna contains sense organs for touch, taste, & smell detects sound
  • Sensory hairs found on parts of the body
  • Palpi for taste

Reproductive System

  • Reproductive organs (ovaries & testes) located  in abdomen
  • Male deposits sperm into female’s seminal receptacle
  • Stored sperm fertilizes eggs as they  are released by female
  • Ovipositor on tip of female’s abdomen is used to lay eggs
  • Separate sexes
  • Lay large number of eggs to ensure survival

Development

  • Most insects go through changes in form & size called metamorphosis
  • Some insects such as silverfish don’t go through metamorphosis
  • Incomplete metamorphosis goes from egg to nymph (immature form that looks like adult but without fully developed wings) to adult (3 stages)
  • Instars are growth periods between molts of nymphs & larva
  • Grasshoppers, termites, & true bugs go through incomplete metamorphosis


HEMIPTERAN (TRUE BUG) NYMPH

  • Complete metamorphosis goes from egg to larva (segmented & wormlike) to pupa  to adult (4 stages)


BUTTERFLY LARVA (CATERPILLAR)

  • Butterflies, beetles, & flies go through complete metamorphosis
  • In pupal stage, larval tissues break down & cells called imaginal disk develops into tissues of the adult
  • Cocoon or chrysalis is a protective case formed around the pupa


BUTTERFLY COCOON

  • Metamorphosis controlled by hormones
    * Brain hormone stimulates the release of molting hormone (ecdysone)
    * When juvenile hormone level high, larva molts
    * When juvenile hormone level low, larva pupates
    * When juvenile hormone absent, adult emerges from pupal case
  • Different stages of metamorphosis eliminates competition between larva & adults for food & space
  • Multi-stage life cycle helps insects withstand harsh weather
  • Different stages have different functions (caterpillar/growth & adult/reproduction)

Defense Mechanisms

  • Bombardier beetle sprays noxious chemical


BOMBARDIER BEETLE

  • Wasps & bees can sting
  • Some insects use camouflage to blend into their environments
  • Some insects taste bad & have warning colorations 


PAPER WASP

  • Mullerian mimicry – poisonous or dangerous species have similar patterns of warning coloration so predators avoid all the species (black & yellow stripes on bees & wasps)
  • Batesian mimicry – species that are nonpoisonous or not bad tasting have colorations that mimic other poisonous or bad tasting species (Viceroy butterfly mimics bad tasting Monarch)

Insect Communication

  • Insects may communicate with each other using sound (cricket chirps), light (firefly), or “dances” (honeybee)
  • Pheromones are chemicals released by some insects to attract mates or mark trails

Insect Behavior

  • Insects may be solitary or social
  • Social insects (bees, ants, & some wasps) live together in groups & share work (division of labor)
  • Social insects have a caste system with different individuals doing different jobs
  • Honeybee caste system:
    * Workers
    – sterile females
    – care for queen & feed her honey and pollen
    – make beeswax for hive
    – fan wings to cool hive
    – eat honey
    – collect nectar, pollen, & royal jelly
    – live about 6 weeks
    – nurse bees care for larva
    – secrete royal jelly to feed new queen
    * Drones
    – males
    – mate with queen
    – feed by workers
    – driven out of hive to conserve food during winter
    * Queen
    – reproductive female
    – mate only once but store sperm for up to 5 years in seminal receptacles
    – feed by workers
    – secretes chemical called queen factor that prevents other females from sexually maturing
    – leaves hive with 1/2 the workers if there is overcrowding


HONEYBEE HIVE

BACK

 

Human Hand Adaptations

 

Human Hand Adaptation

Introduction:        Living things have bodies that are adapted for the places they live and the things they do. Fish have gills so that they can remove oxygen that is dissolved in water. Most plants have green leaves which contain chlorophyll so that they can make food. Jellyfish have stinging cells to capture prey. Birds have hollow spongy bones so that they will be light enough to fly. Arctic animals have layers of fat and thick coats of fur to keep warm in the frigid Arctic climate. There are hundreds of examples of ways that organisms are adapted for a successful lifestyle.       Humans, too, are adapted for the things they do. One of our adaptations is our hand. Humans, as well as monkeys, gorillas, and other primates, have a hand that can grasp objects. We are able to grasp objects because of our opposable thumb. When students first hear or read about the opposable thumb during discussions of human evolution, they may perceive it as an anatomical fact with little seeming importance. In this activity, students will discover which of their simplest daily activities are possible only because of their opposable thumbs, which activities take longer without the use of an opposable thumb, and what sort of human activities would not be likely in the absence of an opposable thumb.   In this lab exercise, you will perform several common actions. Then you will change your hand so that it resembles that of a non-primate animal. You will determine whether or not you can successfully perform the same actions. This will demonstrate how the human hand is adapted for the actions it performs. You will work with a partner to do this exercise.   Materials: (per group)

  • masking tape
  • scissors
  • paper clips
  • zip-lock storage bag
  • plastic fork and knife
  • small amounts of food items to be cut
  • pencil
  • jar with screw-on lid
  • paper
  • roll of tape
  • balloons
  • comb
  • book
  • lace-up shoe
  • clock with a second hand
  • Piece of yarn or string
  • balloon
  • clothes with zippers & buttons

Procedure: Using masking tape, have your partner tightly tape each of your thumbs to the palm of the hand. Then, try to complete the tasks that are listed below. Be careful not to use your thumbs. Have your partner record on your data table how long it takes to do each task with your thumb taped and then with your thumb free. If an activity takes longer than 2 minutes, record the event as unsuccessful . After completing each item, write out the answers to the following questions:

  • Is the task more difficult with or without an opposable thumb?
  • How did you have to change your usual technique in order to complete this task?
  • Do you think organisms without opposable thumbs would carry out this task on a regular basis? Why or why not?

Tasks:

  1. Pick up a single piece of paper. Put it down on your desk.
  2. Pick up a pen or pencil from the table top. Use it to write your name on the piece of paper.
  3. Open a book. Turn single pages in the book.
  4. Unscrew a bottle cap or jar cover.
  5. Use a fork and knife to cut a food item into small pieces.
  6. Tear off a small piece of tape.
  7. Turn on the water faucet. (Complete activity #8!) Turn it off.
  8. Moisten a paper towel and wash and dry the desktop.
  9. Sharpen a pencil.
  10. Cut a circle out of a piece of paper using scissors.
  11. Pick up all the scraps from activity #10 and throw them into the recycling box.
  12. Comb your hair.
  13. Open a door.
  14. Pick up one paper clip. Clip a pile of papers together.
  15. Tie your shoelaces.
  16. Button several buttons.
  17. Zip up your jacket.
  18. Blow up a balloon and tie it.
  19. Tie a knot in a piece of string.
  20. Close a zip-lock bag.

Data:

Table 1 – Time It Took To Perform Various Tasks

 

Task Time Taken for Event: Task Difficulty With Taped Thumb
(More/Less)
Modification Made to complete Task
Thumb Free Thumb Taped
Pick up paper
Write name
Turn book pages
Open jar
Use knife & fork
Tear off tape
Turn faucet on & off
Clean desk top
Sharpen a pencil
Cut out a circle
Pick up the scraps of paper
Comb hair
Open door
Clip papers together
Tie shoelaces
Button & unbutton garment
Use zipper
Blow up & tie balloon
Knot string
Close zip-lock bag

Conclusion:   1. Explain why dog and cat paws are not adapted for doing the six actions you tested.     2. What are cat and dog paws adapted for?     3. Describe how your hand is adapted for doing the actions you tested.       4. You have an opposable thumb. Explain what this means.     5. Why do you feel that human hand adaptations have helped to make humans such a successful species on earth?

 

Ink Chromatography

Chromatography of Inks

Introduction:

One of the main jobs of biochemists is to unravel the complexities of chemical compounds and reduce them to their individual components.  The term chromatography comes from two Greek words, “chromat” meaning color and the word “graphon” meaning to write.  Separation of the components of chemical compounds can be done by using several methods. Liquids can be separate by High Performance liquid Chromatography (HPLC), while the components of gases are separated by Gas Chromatography.  Chromatography is a method for analyzing complex mixtures (such as ink) by separating them into the chemicals from which they are made. Chromatography is used to separate and identify all sorts of substances in police work. Drugs from narcotics to aspirin can be identified in urine and blood samples, often with the aid of chromatography.

Chromatography was first used to separate pigments (colors) in leaves, berries, and natural dyes. Paper chromatography is a technique used to separate, isolate, and identify chemical components of a compound. In paper chromatography, the solid surface is the cellulose fibers in the chromatography paper.  A solvent or developer (water, alcohol, or acetone) is placed in the bottom of the chromatography chamber. The paper acts as a wick to pull the solvent up the paper. The solvent front will “wick” up the chromatography paper by capillary action.  A minute drop of the ink or chemical mixture to be separated is placed near the bottom of the strip of chromatography paper, but slightly above the level of the solvent in the chamber.  As the solvent passes over the drop of ink, the components of the ink dissolve in the solvent. Because the components of the ink do not all dissolve at the same rate, as the components of the mixture move upward, they show up as colored streaks.  The separated substances on the chromatography paper form a color pattern called a chromatogram.

To determine the rate of migration for each pigment or component of the ink, the Rf value for each pigment must be calculated. The Rf value represents the ratio of the distance a pigment moved on the chromatogram relative to the  distance the solvent front moved. Each pigment or compound will have a unique Rf value that scientists can use to identify the substance. The Rf value is calculated using the following formula:

Rf = distance traveled by the compound / distance traveled by the solvent

Objective:

Use the process of paper chromatography to separate the pigments in various markers and then determine the Rf value for each color on your chromatogram.

Materials:

Plastic vials, paper clips, markers in assorted colors, chromatography paper, scissors, pencil

Procedure:

  1. Obtain chromatography vials and chromatography strips, and different color markers so that each person in the group will have two chromatograms.
  2. Cut one end of the chromatography strip to a point. The bottom of the point will mark the starting point for movement of the solvent (H2O).
  3. About 2.0 centimeters from the bottom of the strip, draw a faint horizontal line with pencil. This will mark the starting point for measuring the migration distance of each color.
  4. Using a different color marker for each strip, drop a dot of ink on the center of the horizontal pencil line.  Let this dry a moment & then add more ink to the dot.
  5. Add a small amount of water to the bottom of the chromatography chamber. (The ink dot should be ABOVE the surface of the water.)
  6. Straighten a paper clip and poke a hole through the top of your chromatography strip
  7. Use the paper clip to hang the strip in your chamber. (The straighten paper clip will lay across the top of the chamber.)
  8. MAKE SURE THE TIP OF THE STRIP BUT NOT THE INK IS IMMERSED IN THE WATER!
  9. Notice the separation of the ink as both the solvent and ink travel up the chromatography strip.
  10. Once the solvent front has neared the top of the strip, remove the strip from the chamber and lay it on a piece of paper towel.
  11. Immediately mark the solvent front with a faint pencil line.
  12. Immediately mark the leading edge of each color with an “x”.
  13. Measure, in millimeters, the distance the solvent migrated from the tip of the strip to your solvent front pencil line.
  14. Measure, in millimeters, the distance each color migrated from the point of origin (pencil line where the ink dot was placed) to the leading edge of the color (marked with an “x”.
  15. Record all data in Data table 1.
  16. Calculate and record the Rf value for each color using the formula below.

Rf = distance traveled by the compound / distance traveled by the solvent

Data Table 1

 

Color pen/marker used:

Separated colors
(list top of strip to bottom)
Distance each color traveled

(mm)

Distance solvent (H2O)
(mm)
Rf Value for each color

(Distance color traveled / Distance solvent traveled)

       
       
       
       
       
       
       
       

 

 

 

Color pen/marker used:

Separated colors
(list top of strip to bottom)
Distance each color traveled

(mm)

Distance solvent (H2O)
(mm)
Rf Value for each color

(Distance color traveled / Distance solvent traveled)

       
       
       
       
       
       
       
       

 

 

Questions:

1. Which color of marker did you use?

2. which color separated out first from your ink dot?

3. Why did the inks separate?

 

4. What was your solvent?

5. If you had used markers that weren’t water-soluble, how would you have had to change this lab?

 

6. Why did some inks move a greater distance than others?

 

7. How do scientists use paper chromatography in their investigations?

 

 

Identifying Controls and Variables

Identifying Controls and Variables

 

Smithers thinks that a special juice will increase the productivity of workers. He creates two groups of 50 workers each and assigns each group the same task (in this case, they’re supposed to staple a set of papers). Group A is given the special juice to drink while they work. Group B is not given the special juice. After an hour, Smithers counts how many stacks of papers each group has made. Group A made 1,587 stacks, Group B made 2,113 stacks.

 

Identify the:

1. Control Group

2. Independent Variable

3. Dependent Variable

4. What should Smithers’ conclusion be?

 

5. How could this experiment be improved?

Homer notices that his shower is covered in a strange green slime. His friend Barney tells him that coconut juice will get rid of the green slime. Homer decides to check this out by spraying half of the shower with coconut juice. He sprays the other half of the shower with water. After 3 days of “treatment” there is no change in the appearance of the green slime on either side of the shower.

 

6. What was the initial observation?

Identify the-
7. Control Group

8. Independent Variable

9. Dependent Variable

10. What should Homer’s conclusion be?

 

 

 

Bart believes that mice exposed to microwaves will become extra strong (maybe he’s been reading too much Radioactive Man). He decides to perform this experiment by placing 10 mice in a microwave for 10 seconds. He compared these 10 mice to another 10 mice that had not been exposed. His test consisted of a heavy block of wood that blocked the mouse food. he found that 8 out of 10 of the micro waved mice were able to push the block away. 7 out of 10 of the non-micro waved mice were able to do the same. Identify the-
11. Control Group12. Independent Variable

13. Dependent Variable

14. What should Bart’s conclusion be?

15. How could Bart’s experiment be improved?

Krusty was told that a certain itching powder was the newest best thing on the market, it even claims to cause 50% longer lasting itches. Interested in this product, he buys the itching powder and compares it to his usual product. One test subject (A) is sprinkled with the original itching powder, and another test subject (B) was sprinkled with the Experimental itching powder. Subject A reported having itches for 30 minutes. Subject B reported to have itches for 45 minutes. Identify the-
16. Control Group17. Independent Variable

18. Dependent Variable

19. Explain whether the data supports the advertisements claims about its product.

Lisa is working on a science project. Her task is to answer the question: “Does Rogooti (which is a commercial hair product) affect the speed of hair growth”. Her family is willing to volunteer for the experiment.

20. Describe how Lisa would perform this experiment. Identify the control group, and the independent and dependent variables in your description.

 

 

Hardy-Weinberg Problems

 

POPULATION GENETICS AND THE HARDY-WEINBERG LAW

 

The Hardy-Weinberg formulas allow scientists to determine whether evolution has occurred. Any changes in the gene frequencies in the population over time can be detected. The law essentially states that if no evolution is occurring, then an equilibrium of allele frequencies will remain in effect in each succeeding generation of sexually reproducing individuals. In order for equilibrium to remain in effect (i.e. that no evolution is occurring) then the following five conditions must be met:

  1. No mutations must occur so that new alleles do not enter the population.
  2. No gene flow can occur (i.e. no migration of individuals into, or out of, the population).
  3. Random mating must occur (i.e. individuals must pair by chance)
  4. The population must be large so that no genetic drift (random chance) can cause the allele frequencies to change.
  5. No selection can occur so that certain alleles are not selected for, or against.

Obviously, the Hardy-Weinberg equilibrium cannot exist in real life. Some or all of these types of forces all act on living populations at various times and evolution at some level occurs in all living organisms. The Hardy-Weinberg formulas allow us to detect some allele frequencies that change from generation to generation, thus allowing a simplified method of determining that evolution is occurring. There are two formulas that must be memorized:

 

p2 + 2pq + q2 = 1 and p + q = 1

 

p = frequency of the dominant allele in the population
q = frequency of the recessive allele in the population
p2 = percentage of homozygous dominant individuals
q2 = percentage of homozygous recessive individuals
2pq = percentage of heterozygous individuals

Individuals that have aptitude for math find that working with the above formulas is ridiculously easy. However, for individuals who are unfamiliar with algebra, it takes some practice working problems before you get the hang of it. Below I have provided a series of practice problems that you may wish to try out. Note that I have rounded off some of the numbers in some problems to the second decimal place.

PROBLEM #1    You have sampled a population in which you know that the percentage of the homozygous recessive genotype (aa) is 36%. Using that 36%, calculate the following:

  1. The frequency of the “aa” genotype.
  2. The frequency of the “a” allele.
  3. The frequency of the “A” allele.
  4. The frequencies of the genotypes “AA” and “Aa.”
  5. The frequencies of the two possible phenotypes if “A” is completely dominant over “a.”

PROBLEM #2.    Sickle-cell anemia is an interesting genetic disease. Normal homozygous individuals (SS) have normal blood cells that are easily infected with the malarial parasite. Thus, many of these individuals become very ill from the parasite and many die. Individuals homozygous for the sickle-cell trait (ss) have red blood cells that readily collapse when deoxygenated. Although malaria cannot grow in these red blood cells, individuals often die because of the genetic defect. However, individuals with the heterozygous condition (Ss) have some sickling of red blood cells, but generally not enough to cause mortality. In addition, malaria cannot survive well within these “partially defective” red blood cells. Thus, heterozygotes tend to survive better than either of the homozygous conditions. If 9% of an African population is born with a severe form of sickle-cell anemia (ss), what percentage of the population will be more resistant to malaria because they are heterozygous (Ss) for the sickle-cell gene?

PROBLEM #3.    There are 100 students in a class. Ninety-six did well in the course whereas four blew it totally and received a grade of F. Sorry. In the highly unlikely event that these traits are genetic rather than environmental, if these traits involve dominant and recessive alleles, and if the four (4%) represent the frequency of the homozygous recessive condition, please calculate the following:

  1. The frequency of the recessive allele.
  2. The frequency of the dominant allele.
  3. The frequency of heterozygous individuals.

PROBLEM #4.    Within a population of butterflies, the color brown (B) is dominant over the color white (b). And, 40% of all butterflies are white. Given this simple information, which is something that is very likely to be on an exam, calculate the following:

  1. The percentage of butterflies in the population that are heterozygous.
  2. The frequency of homozygous dominant individuals.

PROBLEM #5.     A rather large population of Biology instructors have 396 red-sided individuals and 557 tan-sided individuals. Assume that red is totally recessive. Please calculate the following:

  1. The allele frequencies of each allele.
  2. The expected genotype frequencies.
  3. The number of heterozygous individuals that you would predict to be in this population.
  4. The expected phenotype frequencies.
  5. Conditions happen to be really good this year for breeding and next year there are 1,245 young “potential” Biology instructors. Assuming that all of the Hardy-Weinberg conditions are met, how many of these would you expect to be red-sided and how many tan-sided?

PROBLEM #6.    A very large population of randomly-mating laboratory mice contains 35% white mice. White coloring is caused by the double recessive genotype, “aa”. Calculate allelic and genotypic frequencies for this population.

PROBLEM #7.    After graduation, you and 19 of your closest friends (lets say 10 males and 10 females) charter a plane to go on a round-the-world tour. Unfortunately, you all crash land (safely) on a deserted island. No one finds you and you start a new population totally isolated from the rest of the world. Two of your friends carry (i.e. are heterozygous for) the recessive cystic fibrosis allele (c). Assuming that the frequency of this allele does not change as the population grows, what will be the incidence of cystic fibrosis on your island?

PROBLEM #8.    You sample 1,000 individuals from a large population for the MN blood group, which can easily be measured since co-dominance is involved (i.e., you can detect the heterozygotes). They are typed accordingly:

 

BLOOD TYPE GENOTYPE NUMBER OF INDIVIDUALS RESULTING FREQUENCY
M MM 490 0.49
MN MN 420 0.42
N NN 90 0.09

 

Using the data provide above, calculate the following:

  1. The frequency of each allele in the population.
  2. Supposing the matings are random, the frequencies of the matings.
  3. The probability of each genotype resulting from each potential cross.

PROBLEM #9.    Cystic fibrosis is a recessive condition that affects about 1 in 2,500 babies in the Caucasian population of the United States. Please calculate the following:

  1. The frequency of the recessive allele in the population.
  2. The frequency of the dominant allele in the population.
  3. The percentage of heterozygous individuals (carriers) in the population.

PROBLEM #10.    In a given population, only the “A” and “B” alleles are present in the ABO system; there are no individuals with type “O” blood or with O alleles in this particular population. If 200 people have type A blood, 75 have type AB blood, and 25 have type B blood, what are the allelic frequencies of this population (i.e., what are p and q)?

PROBLEM #11.    The ability to taste PTC is due to a single dominate allele “T”. You sampled 215 individuals in biology, and determined that 150 could detect the bitter taste of PTC and 65 could not. Calculate all of the potential frequencies.

ANSWERS