Modified True/False
Indicate whether the statement is true or false. If false, change the identified word or phrase to make the statement true.
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1. |
Mendel discovered predictable patterns in the inheritance of traits. _________________________
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2. |
Garden peas are difficult to grow because they mature slowly. _________________________
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3. |
When Mendel cross-pollinated two varieties from the P generation that exhibited contrasting traits, he called the offspring the second filial, or F2, generation. _________________________
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4. |
The contrasting forms of each character studied by Mendel appeared in a 3:1 ratio in the F2 generation. _________________________
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5. |
A dominant allele masks the effect of a recessive allele. _________________________
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6. |
The allele for a recessive trait is usually represented by a capital letter. _________________________
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7. |
Heterozygous individuals have two of the same alleles for a particular gene. _________________________
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8. |
The inheritance of sex-linked traits can be studied by making a pedigree of several generations of a family. _________________________
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9. |
Refer to the illustration above. The father listed in the pedigree is most likely heterozygous for the trait. _________________________
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10. |
Refer to the illustration above. Child #3 probably has the dominant phenotype. _________________________
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11. |
Albinism is caused by a recessive allele. _________________________
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12. |
The phenotype that results from an inherited pair of alleles depends on the instructions in the genes only. _________________________
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13. |
Traits for different characters that are usually inherited together are said to be combined. _________________________
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Multiple Choice
Identify the choice that best completes the statement or answers the question.
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14. |
The passing of traits from parents to offspring is called
a.
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genetics. |
c.
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development. |
b.
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heredity. |
d.
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maturation. |
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15. |
The difference between Mendel’s experiments in the area of heredity and those done by earlier researchers was that
a.
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earlier researchers did not have microscopes. |
b.
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earlier researchers used detailed and numerical procedures. |
c.
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Mendel expressed the results of his experiments in terms of numbers. |
d.
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Mendel used pea plants with both purple and white flowers. |
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16. |
a.
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meiosis. |
c.
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genetics. |
b.
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crossing-over. |
d.
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pollination. |
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17. |
The “father” of genetics was
a.
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A. Knight. |
c.
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Gregor Mendel. |
b.
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Hans Krebs. |
d.
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Charles Darwin. |
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18. |
Garden peas are good subjects for studying heredity because they
a.
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are difficult to grow. |
c.
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produce few offspring. |
b.
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mature quickly. |
d.
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have few traits. |
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19. |
Mendel obtained his P generation by allowing the plants to
a.
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self-pollinate. |
c.
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assort independently. |
b.
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cross-pollinate. |
d.
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segregate. |
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20. |
Step 1 of Mendel’s garden pea experiment, allowing each variety of garden pea to self-pollinate for several generations, produced the
a.
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F1 generation. |
c.
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P generation. |
b.
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F2 generation. |
d.
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P1 generation. |
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21. |
F2 : F1 ::
a.
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P : F1 |
c.
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F1 : P |
b.
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F1 : F2 |
d.
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P : F2 |
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22. |
An allele that is always expressed whenever it is present is called
a.
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dominant. |
c.
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recessive. |
b.
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phenotypic. |
d.
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superior. |
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23. |
The discovery of chromosomes provided a link between the first law of heredity that stemmed from Mendel’s work and
a.
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pollination. |
c.
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mitosis. |
b.
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inheritance. |
d.
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meiosis. |
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24. |
The law of segregation states that
a.
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alleles of a gene separate from each other during meiosis. |
b.
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different alleles of a gene can never be found in the same organism. |
c.
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each gene of an organism ends up in a different gamete. |
d.
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each gene is found on a different molecule of DNA. |
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25. |
Mendel’s law of segregation states that
a.
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pairs of alleles are dependent on one another when separation occurs during gamete formation. |
b.
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pairs of alleles separate independently of one another after gamete formation. |
c.
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each pair of alleles remains together when gametes are formed. |
d.
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the two alleles for a trait segregate independently when gametes are formed. |
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26. |
The phenotype of an organism
a.
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is used to represent its genetic composition. |
b.
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is the physical appearance of a trait. |
c.
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occurs only in dominant individuals. |
d.
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cannot be seen. |
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27. |
If an individual possesses two recessive alleles for the same trait, the individual is said to be
a.
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homozygous for the trait. |
c.
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heterozygous for the trait. |
b.
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haploid for the trait. |
d.
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mutated. |
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28. |
When an individual heterozygous for a trait is crossed with an individual homozygous recessive for the trait, the offspring produced will
a.
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all have the same genotype. |
b.
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show two different phenotypes. |
c.
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show three different phenotypes. |
d.
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all have the same phenotype. |
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29. |
Tallness (T) is dominant to shortness (t) in pea plants. Which of the following represents a genotype of a pea plant that is heterozygous for tallness?
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30. |
homozygous : heterozygous ::
a.
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heterozygous : Bb |
c.
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probability : chance |
b.
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gg : Gg |
d.
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factor : gene |
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31. |
Mendel’s finding that the inheritance of one trait had no effect on the inheritance of another became known as the
a.
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law of dominance. |
b.
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law of universal inheritance. |
c.
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law of separate convenience. |
d.
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law of independent assortment. |
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In humans, having freckles (F) is dominant to not having freckles (f). The inheritance of these traits can be studied using a Punnett square similar to the one shown below.
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32. |
Refer to the illustration above. The child represented in box 1 in the Punnett square would
a.
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be homozygous for freckles. |
b.
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have an extra freckles chromosome. |
c.
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be heterozygous for freckles. |
d.
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not have freckles. |
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33. |
Refer to the illustration above. The parents shown in the Punnett square could have children with a phenotype ratio of
a.
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1:2:1. |
c.
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3:1. |
b.
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4:0. |
d.
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2:2. |
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34. |
Refer to the illustration above. Which box in the Punnett square represents a child who does not have freckles?
a.
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box 1 |
c.
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box 3 |
b.
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box 2 |
d.
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box 4 |
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35. |
Refer to the illustration above. The child in box 3 of the Punnett square has the genotype
a.
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FF. |
c.
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ff. |
b.
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Ff. |
d.
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FfFf. |
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In rabbits, black fur (B) is dominant to brown fur (b). Consider the following cross between two rabbits.
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36. |
Refer to the illustration above. The device shown, which is used to determine the probable outcome of genetic crosses, is called a
a.
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Mendelian box. |
c.
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genetic graph. |
b.
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Punnett square. |
d.
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phenotypic paradox. |
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37. |
Refer to the illustration above. Both of the parents in the cross are
a.
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black. |
c.
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homozygous dominant. |
b.
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brown. |
d.
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homozygous recessive. |
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38. |
Refer to the illustration above. The phenotype of the offspring indicated by box 3 would be
a.
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brown. |
c.
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a mixture of brown and black. |
b.
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black. |
d.
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white. |
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39. |
Refer to the illustration above. The genotypic ratio of the F1 generation would be
a.
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1:1. |
c.
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1:3. |
b.
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3:1. |
d.
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1:2:1. |
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40. |
What is the expected genotypic ratio resulting from a homozygous dominant ´ heterozygous monohybrid cross?
a.
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1:0 |
c.
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1:2:1 |
b.
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1:1 |
d.
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1:3:1 |
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41. |
What is the expected genotypic ratio resulting from a heterozygous ´ heterozygous monohybrid cross?
a.
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1:2:1 |
c.
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1:2 |
b.
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1:3:1 |
d.
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1:0 |
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42. |
What is the expected phenotypic ratio resulting from a homozygous dominant ´ heterozygous monohybrid cross?
a.
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1:3:1 |
c.
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2:1 |
b.
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1:2:1 |
d.
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1:0 |
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43. |
The unknown genotype of an individual with a dominant phenotype can be determined using a
a.
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ratio. |
c.
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probability formula. |
b.
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dihybrid cross. |
d.
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test cross. |
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44. |
What is the probability that the offspring of a homozygous dominant individual and a homozygous recessive individual will exhibit the dominant phenotype?
a.
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0.25 |
c.
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0.66 |
b.
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0.5 |
d.
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1.0 |
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45. |
Probability is calculated by dividing the number of one kind of possible outcome by the
a.
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number of other kinds of outcomes. |
b.
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total number of all possible outcomes. |
c.
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number of genes being considered. |
d.
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total number of offspring produced. |
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46. |
If a characteristic is sex-linked, the gene for it is found on
a.
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a sex chromosome. |
c.
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a linked chromosome. |
b.
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an autosome. |
d.
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an allele. |
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47. |
Since the allele for colorblindness is located on the X chromosome, colorblindness
a.
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cannot be inherited. |
c.
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is sex-linked. |
b.
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occurs only in adults. |
d.
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occurs only in females. |
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48. |
A diagram in which several generations of a family and the occurrence of certain genetic characteristics are shown is called a
a.
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Punnett square. |
c.
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pedigree. |
b.
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monohybrid cross. |
d.
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family karyotype. |
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49. |
In humans, eye color and height are controlled by
a.
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simple dominance. |
c.
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polygenic inheritance. |
b.
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multiple alleles. |
d.
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incomplete dominance. |
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50. |
Which of the following traits is controlled by multiple alleles in humans?
a.
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eye color |
c.
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colorblindness |
b.
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blood type |
d.
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albinism |
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51. |
What would be the blood type of a person who inherited an A allele from one parent and an O allele from the other?
a.
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type A |
c.
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type AB |
b.
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type B |
d.
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type O |
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52. |
Which of the following is not an outcome of the environment modifying a phenotype?
a.
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the changing of the color of an animal’s fur as the temperature changes |
b.
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the increased intelligence of a person who attended school for many years |
c.
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the very short stature of a kind of tree that grows at a high altitude in comparison with the same kind of tree growing at a lower altitude |
d.
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the pink-flowered snapdragons that result from crosses between red-flowered and white-flowered snapdragon plants |
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53. |
Genes that are close together on a single chromosome are considered to be
a.
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alleles. |
c.
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independent. |
b.
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homozygous. |
d.
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linked. |
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