Ap Biology Notebook

AP Biology Notebooks

Special Instructions:

1.    Use a 2″, 3-ring binder as your notebook.

2.    The cover of your notebook should have your name, subject, & period only!

3.    A master cover sheet with your name & period must be clipped into your notebook as the first sheet.

4.    Dividers with tabs labeled with the name of each section must be included.

5.    All papers must be clipped into the notebook in the correct order by units.

6.    Notebooks must be brought to class each day!

7.    Students will only receive credit for their notebook each nine weeks IF it is kept in order!

Notebook Sections:
SECTION 1 – SYLLABUS

SECTION 2 – HANDOUTS to BE SAVED ALL YEAR

  • Website sheet, class rules, notebook guidelines, safety rules, how to write abstracts and lab reports

SECTION 3 – UNIT WORK

  • Include a cover sheet for each unit with its number & title
  • Unit work should be in the following order — outlines, notes, worksheets, handouts, study guides, etc

SECTION 4 – COMPUTERIZED GRADE REPORTS

  • Printed from computer every 2 – 3 weeks

NOTE: A separate notebook will be kept for labs!
Click here for Lab Notebook instructions

 

AP Unit 4 Genetics Study Guide

 

                          Unit IV   Genetics Study Guide     

  • Be able to determine the probability of getting a number by rolling a pair of dice.
  • Be able to work monohybrid crosses for complete and incomplete dominance and show genotypes, phenotypes, and ratios.
  • Be able to work dihybrid crosses and determine genotypes, phenotypes, and ratios.
  • Be able to explain and give examples of codominance, epitasis, polygenic inheritance, sex-linked inheritance….
  • Be able to work a problem on colorblindness.
  • Be able to list and explain Mendel’s laws of heredity.
  • Be able to discuss Morgan, Sutton, and Sturtevant’s contributions to the understanding of chromosomal inheritance.
  • Be able to define linkage and explain how it interferes with independent assortment.
  • Be able to predict the probability of a genotype occurring for a cross involving 4 traits. (Rule of Multiplication)
  • Be able to name and describe a genetic defect caused by nondisjunction of sex chromosomes.
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AP Unit 2 Cell Study Guide

Unit 2    Cells Study Guide

How do bacterial cells differ from animal cells?
Cells that make proteins would have a large number of ________?
What protein makes up the cytoskeleton & gives a cell its shape?
How do phospholipids in the cell membrane move?
If a body cell had 24 chromosomes, how many chromosomes would be in the gamete?
If chromosomes have the same genes in the same location & the same banding pattern, they are said to be ___?
What chemical in animal cell membranes maintains their fluid nature?
Facilitated diffusion & active transport both require what molecules in cell membranes?
Name the 3 stages of cell signaling.
How does a sexual life cycle increase genetic variation?
What organelle converts light energy into chemical energy?
What will happens to the chromosomes in a cell that passes the restriction checkpoint?
What type of scope is needed to study the internal structure of a cell?
Does the cytoskeleton limit cell size?
Describe the signal-transduction pathway in animals.
What type of cells do not reproduce more cells by mitosis & cytokinesis?
Is diffusion active or passive transport?
How can you determine if a cell is in an isotonic solution?
What organelle makes lipids?
What is the function of these cell structures — mitochondrion, chloroplast, ribosome, lysosome, cell wall, & chromosomes?
How does CO2 move into a cell?
Name the parts of the cytoskeleton.
What cell organelles have two membranes?
What is active transport?
How does potassium move into & out of a cell?
How does one rotting piece of fruit affect the ripening of others?
Name all structures in a cell responsible for movement.
In what organisms is cell signaling less important?
If a cell has 92 chromosomes at the start of mitosis, how many will be in the daughter cells?
Describe paracrine signaling.
When do tetrads from in a cell?
What is the function of tyrosine-kinase receptors?
At what point are chromatids attached to each other?
What is the function of glycolipids & glycoproteins in animal cell membranes?
How does telophase of mitosis differ in plant & animal cells?
When the signal molecule changes the protein receptor, what process begins?
What is membrane potential?
What effect would calcium deficiency have on a plant?
Besides the nucleus, where else can DNA be found in a cell?
Do plant cells have mitochondria? Why or why not?
Which proteins in the cell membrane function in active transport?
Why would bacterial cells not be capable of phagocytosis?
Why are eukaryotic cells larger than prokaryotic cells?
What is the purpose of cell fractionation?
Through what type of junctions do ions travel between cells?
How can you determine if a karyotype is from a male or female?
How do genetic differences in clones occur?
If the spindle can not form, at what stage will mitosis no longer proceed?
What will be true of cells that undergo mitosis but not cytokinesis?
What cellular structure helps form the cleavage furrow in animal cells?
How do receptor proteins in a membrane act like enzymes?
What occurs during prophase of mitosis?
By what process do large solids move into a cell?
Does the movement of oxygen & carbon dioxide across cell membranes require energy?
Describe the interior of chloroplasts & mitochondria.
How is synaptic signaling different than hormone signaling?
What is a karyotype?
How do daughter & parent cells compare with each other?
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AP Sample 6 Lab 5 – Cellular Respiration

 

 

Lab 6 Cellular Respiration

 

 

Introduction

 

Cellular respiration is the release of energy from organic compounds by metabolic chemical oxidation in the mitochondria within each cell. Enzyme mediated reactions are required. The equation for cellular respiration is:

C6H12O6 + 6 O2 à 6 CO2 + 6 H2O + 686 kilocalories of energy/mole of glucose oxidized

Several different measures can be taken from this equation. The consumption of oxygen, which will tell you how many moles of oxygen are consumed during cellular respiration. That is what was measured in this lab. The production of CO2 can also be measured. And of course the release of energy can be measured. Cellular respiration is a catabolic pathway and the mitochondria houses most of the metabolic equipment for cellular respiration. It will break down glucose in what we call an exergonic reaction. Like previously said, the consumption of oxygen molecules will be measured in a gas form. One must know the physical laws of gases when working with them. The laws are summarized by the following equation.

PV=Nrt

Where:

P stands for the pressure of the gas

V is the volume of the gas

n is the number of molecules of gas

R is the gas constant (fixed value)

T is the temperature of the gas ( in K° )

The CO2 produced during cellular respiration will be removed by potassium hydroxide (KOH) and will form a solid potassium carbonate (K2CO3) when the following reaction occurs: CO2 + 2 KOH à K2CO3+ H2O

Since the CO2 is removed, the change in the volume of gas in the respirometer will be directly related to the amount of oxygen consumed. If the water temp and volume stay constant then the water will move toward the region of lower pressure. During respiration, oxygen will be consumed and its volume will be reduced because the CO2 is being converted to a solid. The net result is a decrease in gas volume in the tube and a decrease in pressure of the tube. The vial with beads will detect any atmospheric changes.

Hypothesis

Several different things will affect the rate of O2 consumption. The non germinating peas will have a lower rate than the germinating peas and the coldness of the water will slow the rates.

Materials

The materials used for this lab were: a 100 mL graduated cylinder, 6vials,germinating peas, dry peas, glass beads, 2 water baths, absorbent cotton and non-absorbent cotton, weights, KOH, water, stoppers, pipettes, rubber bands, masking tape, glue, thermometer, ice, a pencil, and paper.

Methods

Set up a 25° C and a 10° C water bath. Ice may be used to obtain 10° C.

Respirometer 1:Obtain a 100 mL graduated cylinder and fill it with 50 mL of H2O.

Drop in 25 germinating peas. Determine the amount of water displaced. Pea volume =11 mL. Take peas out and place on paper towel.

Respirometer 2: refill cylinder with 50 mL of H2O. Drop 25 dry peas into the cylinder. Add glass beads to obtain the same volume that you got in respirometer 1. Remove peas and beads to a paper towel.

Respirometer 3: Add 50 mL of water to the cylinder. Put only beads in to get an equivalent volume to the first 2 respirometers. Put on paper towel when finished. Repeat respirometer 1 steps for respirometer 4. And 2 for 5. And 3 for 6. Listen to your teacher on how and where to set up the respirometers. Now fill your vials with the required items shown in the table and in figure 5.1. Seal the vials after your items have been put in to stop any gas or water leaks. Place a weighted collar onto the bottom of your vials so they will stay submerged in the water baths. During equilibration use masking tape attached to each side of the water baths to hold the respirometers out of water for 7 minutes. Vials 1-3 should be in the 25° C water bath and vials 4-6 should be in the 10° C water bath. Finally submerge totally the respirometers and let them equilibrate for 3 more minutes. Read the water line where the oxygen is and record in intervals of 5 minutes all the way up to 25 minutes. Record in table 5.1.

 

Results

Table 5.1: Measurement of O2 Consumption by Soaked and Dry Pea Seeds at Room Temperature and 10° C Using Volumetric Methods

 

 

Beads Alone

Germinating Peas

Dry Peas and Beads

Reading at time X Diff. Reading at time X Diff. Corrected Diff. Reading at time X Diff. Corrected Diff.
Initial-0 1.35 1.62 1.32
0-5 1.33 .02 1.20 .42 .4 1.32 .0 .02
5-10 1.33 .02 1.12 .50 .48 1.3 .02 .0
10-15 1.32 .03 1.02 .60 .57 1.29 .03 .0
15-20 1.32 .03 .92 .7 .67 1.3 .02 .01
 

Initial-0

1.48 1.37 1.46
 

0-5

1.48 .0 1.15 .22 .22 1.45 .01 .01
 

5-10

1.45 .03 .98 .39 .36 1.44 .02 .01
 

10-15

1.43 .05 .84 .53 .48 1.43 .03 .02
 

15-20

1.41 .07 .70 .67 .6 1.41 .05 .02

 

 

In this activity, you are investigating both the effects of germination versus non-germination and warm temperature versus cold temperature on respiration rate. Identify the hypothesis being tested on this activity.
The nongerminating peas will have a slower rate of respiration than the germinating peas and the coldness of the water will slow down the rate as it gets colder.

 

This activity uses a number of controls. Identify at least three of the controls, and describe the purpose of each.
The three controls are the beads in one vial controlling the barometric pressure, the KOH keeps equality in the consumption of CO2, and the time intervals give each vial the same amount of time so the results will not be affected.

Describe and explain the relationship between the amount of oxygen consumed and time.
The relationship was pretty constant, there may have been a gradual rising in O2 consumption.

5.

 

 

Condition

 

Calculations

 

Rate in mL O2/ minute

 

Germinating Peas/ 10 oC

 

(1.62-.92)

20

.035
 

Germinating Peas/ 20 oC

 

(1.37-.7)

20

.0335
 

Dry Peas/ 10 oC

 

(1.32-1.30)

20

.001
 

Dry Peas/ 20 oC

(1.46-1.41)

20

.0025

 

Why is it necessary to correct the readings from the peas with the readings from the beads?
The beads were just a control, experiencing no gas change.

 

Explain the effects of germination (versus non-germination) on pea seed respiration.
The germinating seeds had a higher metabolic rate and therefore consumed more oxygen than the nongerminating.

Above is a sample graph of possible data obtained for oxygen consumption by germinating peas up to about 8 oC. Draw in predicted results through 45 oC. Explain your prediction.
Once the temperature gets above about 30 degrees C, the enzymes will denature and that will be the end of respiration.

 

What is the purpose of KOH in this experiment?
The KOH will take the CO2 and turn it to a precipitant at the bottom of the vial and it will have no affect on the O2 readings.

 

Why did the vial have to be completely sealed under the stopper?
The vial had to be sealed or gas would leak out and water could leak in and affect the results.

 

If you used the same experimental design to compare the rates of respiration of a 35g mammal at 10 oC, what results would you expect? Explain your reasoning.
Respiration would be higher in the mammal because they are warm-blooded.

 

If respiration in a small mammal were studied at both room temperature (21 oC) and 10 oC, what results would you predict? Explain your reasoning.
The rate of respiration would be higher in the 21-degree bath because the mammal would perform better when its body was more comfortable.

 

Explain why water moved into the respirometer pipettes.
The water moved in the vial because it was fully submerged in water but it came to a stop when it met the oxygen coming out of the vial.

14. Design an experiment to examine the rates of cellular respiration in peas that have been germinating for 0, 24, 48, and 72 hours. What results would you expect? Why?
You could put peas in vials each from a time interval above. You would have a vial with just started germinating peas, one with 24 hour germinating peas, another with 48 hour peas, and the last with 72 hour peas. Place them in a room temp water bath. Take readings at intervals of 5 min up to 20 min. The 72-hour peas should have more O2 consumption because they will use more oxygen because they have been germinating the longest. The just started germinating peas would use the least O2 because they haven’t been germinating vary long. The other two will be in the middle of the “just started peas” and the “72 hour peas”.

 

Error Analysis

 

Many errors could have been made in this lab. There could have been miscalculations when trying to equal the pea volumes. The stoppers might not have been sealed and gas could have been lost from the vials affecting the results with vengeance. The water temperatures had to be maintained precisely or the results would not be what they should be. There was also a lot of math in this lab when figuring results and many numbers could have been affected by this poor math.

 

Disussion and Conclusion

This lab showed many things about thew rates of cellular respiration. This lab showed that germinating peas consume more O2 than nongerminating peas. The colder temperature also slowed the rate of oxygen consumption. The oxygen could be clearly seen because of the following reaction

CO2+2KOH à K2O3 +H2O

This reaction gets rid of the CO2 so that it would not affect the readings of oxygen. It is absorbed by KOH to give you a precipitant K2CO3 + H2O. I conclude that the rate of O2 consumption is directly proportional to the respiration rate in that when the rate increases the gas consumption increases. When the gas consumption is low then the rate is low. Organisms go through cellular respiration more proficiently when the body of the organism is comfortable with its outside temp and environment. This lab showed many things affecting the rate of cellular respiration.

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AP Sample Lab 12 Dissolved Oxygen

 

Dissolved Oxygen and Primary Aquatic Productivity
Laboratory 12

 

Introduction

 

Dissolved oxygen levels are an extremely important factor in determining the quality of an aquatic environment. Dissolved oxygen is necessary for the metabolic processes of almost every organism.

Terrestrial environments hold over 95% more oxygen than aquatic environments. Oxygen levels in aquatic environments are very vulnerable to even the slightest change. Oxygen must be constantly be replenished from the atmosphere and from photosynthesis. There are several factors that effect the dissolved oxygen levels in aquatic environments.

Temperature is inversely proportional to the amount of dissolved oxygen in water. As temperature rises, dissolved oxygen levels decrease.

Wind allows oxygen to be mixed into the water at the surface. Windless nights can cause lethal oxygen depletions in aquatic environments.

Turbulence also increases the mixture of oxygen and water at the surface. This turbulence is caused by obstacles, such as rocks, fallen logs, and water falls, and can cause extreme variations in oxygen levels throughout the course of a stream.

The Trophic State is the amount of nutrients in the water. There are two classifications: oligotrophic and eutrophic. Oligotrophic lakes are oxygen rich, but generally nutrient poor. They are clearer and deeper than eutrophic lakes and are younger. Oxygen levels are constant. Eutrophic lakes are more shallow and nutrient rich. The oxygen levels constantly fluctuate from high to low.

Primary production is the energy accumulated by plants since it is the first and basic form of energy storage. The flow of energy through a community begins with photosynthesis. All of the sun’s energy that is used is termed gross primary production. The energy remaining after respiration and stored as organic matter is the net primary production, or growth. The equation for photosynthesis is as follows:

12H2O + 6CO2 → C6H12O6 + 6O2 + 6H2O

There are two ways to measure primary production, the oxygen method and the carbon dioxide method. The oxygen method uses a dark and light bottle to compare the amount of oxygen produced in photosynthesis and used in respiration. Respiration rate is determined by subtracting the dark bottle from the initial bottle. The carbon dioxide method places a transparent plastic bag over one sample and a dark plastic bag over the other. Each bottle is set up so that air is drawn through the enclosure and passes over carbon dioxide-absorbent material. The amount of carbon under the dark bag is respiration, while the amount of carbon under the transparent bag is the amount of photosynthesis minus the amount of respiration.

There are three main gases dissolved in aquatic environments: nitrogen, oxygen, and carbon dioxide. Most gases obey Henry’s law, which says that at a constant temperature, the amount of gas absorbed by a given volume of liquid is proportional to the pressure in the atmosphere that the gas exerts.

c = K ×p

                                                             c = Concentration of the gas that is absorbed

K = Solubility factor

                     p = Partial pressure of the gas

 

Altitude may affect the p value of the equation. Higher altitudes decrease the solubility of gases in water. Temperature also has an affect, as temperature rises, solubility decreases. Salinity, the occurrence of various minerals in solution, also lowers the solubility of gases in water.

The method used to determine the amount of dissolved oxygen in the water is the Winkler titrametric method. It involves a series of chemical reactions which ends with a quantity of free iodine equal to the amount of oxygen in the sample. The iodine is then titrated with thiosulfate to find this quantity.

 

Hypothesis

The temperature and amount of light an aquatic environment receives greatly affects the dissolved oxygen levels, along with the amount of primary aquatic productivity.

 

Materials

 

Measurement of Dissolved Oxygen

This part of the lab required a sample bottle of water from a natural source, a BOD bottle, thermometer, mangonous sulfate, alkaline iodide, thiosulfate, a 2-mL pipette, sulfuric acid, a 20-mL sample cup, a white piece of paper, starch solution, and a nomograph.

Measurement of Primary Productivity

Part B required a sample bottle of water from a natural source, 7 BOD bottles, aluminum foil, 17 cloth screens, rubber bands, a light, thermometer, concavity slides, light microscope, mangonous sulfate, alkaline iodide, thiosulfate, a 2-mL pipette, sulfuric acid, a 20-mL sample cup, a white piece of paper, starch solution, and a nomograph.

Productivity Simulation

This section required pencil, paper, calculator, and graph paper.

 

Methods

 

Measurement of Dissolved Oxygen

The sample bottle was filled completely so that there were no air bubbles in the bottle. The sample bottle was left in the refrigerator until it reached 5° C. A BOD bottle was filled with the sample water until it contained no air bubbles.

Eight drops of mangonous sulfate were added to the bottle. Next, eight drops of alkaline iodide was added and the precipitate manganous hydroxide was formed. The bottle was inverted several times and then allowed to settle until the precipitate was below the shoulders of the bottle. While the solution was settling, a 2mL pipette was filled with thiosulfate. A scoop of sulfuric acid was added, and the bottle was inverted until all of the precipitate dissolved. The sample turned a clear yellow.

20mL of the sample were poured into the sample cup. The cup was placed on a white sheet of paper so that the color changes could be observed. 8 drops of starch solution were added to the sample, making it turn purple. The sample was then titrated with the thiosulfate. One drop of the titrant was added at a time until the color changed to a pale yellow color.

A nomograph was used to determine the percent saturation of dissolved oxygen in the sample.

Measurement of Primary Productivity

A second sample bottle was filled from a natural source making sure there were no air bubbles. Seven BOD bottles were filled completely with the sample with no air bubbles. The first bottle was labeled #1-Initial. The second bottle served as the dark bottle and was labeled #2-Dark. The other five bottles were labeled according to the light intensity: #3-100%, #4-65%, #5-25%, #6-10%, and #7-2%.

Bottle #2 was wrapped completely in aluminum foil so that it received no light. The other five bottles were wrapped in screens to produce the desired light intensity. Bottle #3 had no screens, bottle #4 had 1 screen, bottle #5 had 3 screens, bottle #6 had 5 screens, and bottle #7 had 8 screens. The screens were held in place with rubber bands. Bottles #2-7 were placed under a light source and left overnight.

Bottle #1 was fixed by following the Winkler method. Eight drops of mangonous sulfate were added to the bottle. Next, eight drops of alkaline iodide was added and the precipitate manganous hydroxide was formed. The bottle was inverted several times and then allowed to settle until the precipitate was below the shoulders of the bottle. A scoop of sulfuric acid was added, and the bottle was inverted until all of the precipitate dissolved. The sample turned a clear yellow. It was left at room temperature until the other samples were processed.

A wet mount was observed under a light source, so that the different organisms present could be identified.

The next day, bottles #2-7 were fixed by following the same method used on Bottle #1. The dissolved oxygen levels were determined in each of the seven bottles by titrating. 20mL of the sample were poured into the sample cup. The cup was placed on a white sheet of paper so that the color changes could be observed. 8 drops of starch solution were added to the sample, making it turn purple. The sample was then titrated with the thiosulfate. One drop of the titrant was added at a time until the color changed to a pale yellow color.

Productivity Simulation

The respiration data from Part B was converted to carbon productivity. The data was graphed with comparison to water depths.

 

Results

 

A. Measurement of Dissolved Oxygen

 

Table 1

Dissolved Oxygen Concentration

 

 

 

Temperature

 

Dissolved Oxygen (mg/l)

 

% Dissolved Oxygen

 

5° C

2.0 mg/l 16%
 

21.5° C

1.28 mg/l 19%

 

How does temperature affect the solubility of oxygen in water?

 

As temperature goes up the solubility of oxygen in water goes down. They are inversely proportional.

 

How does salinity affect the solubility of oxygen in water?

 

The occurrence of various minerals in solution lowers the solubility of oxygen in water.

 

Would you expect to find a higher dissolved oxygen content in a body of water in winter or summer?

 

Oxygen levels would be higher in the winter because the solubility of oxygen in water is higher at lower temperatures.

 

List and discuss three factors that could influence the dissolved oxygen concentration of a body of water.

 

Temperature-As temperature goes up solubility goes down.

Pressure- As pressure decreases solubility decreases. Pressure is directly affected by altitude

Salinity-The occurrence of various minerals in solution lowers the solubility of oxygen in water.

 

Do you think it would be wise to stock a pond with game fish if it had a dissolved oxygen content of 3ppm? Why or why not?

 

It would not be wise to stock a pond with an oxygen level of 3ppm with game fish because their optimal levels range from 8 to 15ppm. A concentration of dissolved oxygen less than 4ppm is stressful to most forms of aquatic life.

B. Measurement of Primary Productivity

 

Respiration Rate = 4.6 ml O2/l

 

Table 3

Gross and Net Productivity/ Respiration Rate

 

 

 

Percent Light

 

Dissolved Oxygen

 

Gross Productivity

 

Net Productivity

 

Gross Productivity (mg C/m3)

 

Initial

9.2 ml O2/l NA NA NA
 

Dark

4.6 ml O2/l NA NA NA
 

100%

6.4 ml O2/l 1.8 ml O2/l -2.8 ml O2/hr 0.965 mg C/m3
 

65%

3.8 ml O2/l -0.8 ml O2/l -5.4 ml O2/hr -0.429 mg C/m3
 

25%

4.5 ml O2/l -0.1 ml O2/l -4.7 ml O2/hr -0.054 mg C/m3
 

10%

3.7 ml O2/l -0.9 ml O2/l -5.5 ml O2/hr -0.482 mg C/m3
 

2%

4.0 ml O2/l -0.6 ml O2/l -5.2 ml O2/hr -0.322 mg C/m3

 

 

 

Were any of the samples light limited? Why?

 

Each sample was given a certain amount of light by the use of aluminum foil and screen. Bottle #2 received no light, because it was covered with aluminum foil. Bottles #3-7 had varying numbers of screen ranging from 100% to 2% light intensity.

Productivity Simulation

 

Based on your analysis, which lake is more productive?

 

Lake 2 would be more productive because there is more oxygen available in the lower layers than in Lake 1.

 

What is used as the basis for measuring primary productivity?

 

Primary productivity is measured by the amount of dissolved oxygen available in the water. This shows the amount of oxygen produced by photosynthesis and the amount used by respiration.

 

Error Analysis

 

The Part A experiment was affected mainly by human error and inexperience with the Winkler method. The sample may have been over exposed to the air or the temperature may have changed before the fixing procedure was finished.

The original Part B experiment performed was unsuccessful. There were substantially more decomposing bacteria than photosynthetic organisms in the water sample use. The initial dissolved oxygen level was only 0.84 causing the other samples to have little or no oxygen. The amount of oxygen was so low that it was unable to form the free iodine and could not be titrated. This left no quantifiable data to use in graphs and tables.

 

Discussion and Conclusion

 

Temperature is inversely proportional to the solubility of gases in water. As temperature rose the dissolved oxygen levels should have decreased. This was qualified in the data obtained from this experiment, as the 5° C water sample measured 2.0 mg/l and the 21.5° C sample measured 1.28 mg/l. The percent saturation showed that even though the 5° C sample contained more oxygen it was still less saturated than the 21.5° C sample.

Part B of the lab was used to measure dissolved oxygen concentration, gross and net productivity, and respiration rate of the water samples. It also demonstrated the effect of light and nutrients on photosynthesis. In aquatic environments oxygen production and oxygen usage must be balanced to prevent anoxia. In the original experiment this balance was interrupted by the limiting of light by screens and aluminum foil. The amount of respiration in all of the bottles exceeded the amount of photosynthesis occurring. This was due to the types of organisms present in the sample, which was mainly decomposing bacteria and protozoan. The experiment was correct in its methods however the data received was not quantifiable. This absence of sufficient oxygen in the water samples is an indicator of poor water quality, which may require further investigation. Excess pollution or dumping of wastes into the water sample is a suspected cause of the poor water quality.

The data used in this report shows that as more light was limited, there was less dissolved oxygen present in the water. This is caused because photosynthesis cannot occur without sufficient light.

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